C*U
2 楼
这两日在温习86版的红楼，31、32集，感触良多，一言难尽。。。
h*a
3 楼
USA的，很好看.
==以下介绍转载自天涯小筑 转载请注明出处==
USA秋季新剧《不是冤家不聚头》（White Collar）10月23日首播。这是一部相当有意思的剧集（USA最近几部新剧的品质都非常不错）－－虽然类型上依然是美国人最喜爱的「罪案调查」，但形式上又有新的「花样」。故事讲述两个男人联手侦破FBI顶级要案，抓获最狡诈的罪犯的故事。这两个人一个是诈骗高手，另一个是专门捉拿诈骗高手的FBI 警探。他们本来没有合作的可能，但事实证明他们合作得很好－－除了经常因意见相左而争吵之外。
Neal Caffrey（Matt Bomer扮演，"Chuck"，"Tru Calling"）是一位英俊帅气但是臭名昭著的诈骗犯，最近刚刚从安全等级最高的联邦监狱中成功逃脱。Peter Burke（Tim DeKay扮演，"Tel l Me You Love Me"）是一位出色的FBI警探，Neal的死敌。Peter将Neal抓住，然后又故意让他脱逃，自然有他的打算。Elizabeth Burke（Tiffani Thiessen扮演，"What About Brian"，"Fastlane"）是P
==以下介绍转载自天涯小筑 转载请注明出处==
USA秋季新剧《不是冤家不聚头》（White Collar）10月23日首播。这是一部相当有意思的剧集（USA最近几部新剧的品质都非常不错）－－虽然类型上依然是美国人最喜爱的「罪案调查」，但形式上又有新的「花样」。故事讲述两个男人联手侦破FBI顶级要案，抓获最狡诈的罪犯的故事。这两个人一个是诈骗高手，另一个是专门捉拿诈骗高手的FBI 警探。他们本来没有合作的可能，但事实证明他们合作得很好－－除了经常因意见相左而争吵之外。
Neal Caffrey（Matt Bomer扮演，"Chuck"，"Tru Calling"）是一位英俊帅气但是臭名昭著的诈骗犯，最近刚刚从安全等级最高的联邦监狱中成功逃脱。Peter Burke（Tim DeKay扮演，"Tel l Me You Love Me"）是一位出色的FBI警探，Neal的死敌。Peter将Neal抓住，然后又故意让他脱逃，自然有他的打算。Elizabeth Burke（Tiffani Thiessen扮演，"What About Brian"，"Fastlane"）是P
c*9
4 楼
I have a c++ function with this signature void f(char ** input)
char a[10] = "":
strcpy( a, anotherstring.c_str());
f( &a );
The compiler complain about can not convert the type for function f
parameter.
any ideas what is wrong?
thanks,
char a[10] = "":
strcpy( a, anotherstring.c_str());
f( &a );
The compiler complain about can not convert the type for function f
parameter.
any ideas what is wrong?
thanks,
A*e
5 楼
我文盲看到红楼梦就打瞌睡。。
【在 C*****U 的大作中提到】
: 这两日在温习86版的红楼，31、32集，感触良多，一言难尽。。。
【在 C*****U 的大作中提到】
: 这两日在温习86版的红楼，31、32集，感触良多，一言难尽。。。
t*g
6 楼
男的太英俊了， 有点太太英俊了， 呵呵， 女生会喜欢看的
X*r
7 楼
'&a' is of type 'char (*)[10]', not of type 'char **'.
【在 c*******9 的大作中提到】
: I have a c++ function with this signature void f(char ** input)
: char a[10] = "":
: strcpy( a, anotherstring.c_str());
: f( &a );
: The compiler complain about can not convert the type for function f
: parameter.
: any ideas what is wrong?
: thanks,
【在 c*******9 的大作中提到】
: I have a c++ function with this signature void f(char ** input)
: char a[10] = "":
: strcpy( a, anotherstring.c_str());
: f( &a );
: The compiler complain about can not convert the type for function f
: parameter.
: any ideas what is wrong?
: thanks,
C*U
8 楼
你也太薄情郎了。
我看一次震撼一次，几个场景我经常都会落泪。。。
那样的演员，那样的眼神，那样的音乐，怎么会打瞌睡？
【在 A*****e 的大作中提到】
: 我文盲看到红楼梦就打瞌睡。。
我看一次震撼一次，几个场景我经常都会落泪。。。
那样的演员，那样的眼神，那样的音乐，怎么会打瞌睡？
【在 A*****e 的大作中提到】
: 我文盲看到红楼梦就打瞌睡。。
l*n
9 楼
好看，我一直在追着呢
c*9
10 楼
I think a is name of an array of char, so a is pointer to the a[0], which
should be of type char*, is that correct?
if so &a should be of type char** ?
thanks...
should be of type char*, is that correct?
if so &a should be of type char** ?
thanks...
t*u
11 楼
凯蒂也不错
【在 t******g 的大作中提到】
: 男的太英俊了， 有点太太英俊了， 呵呵， 女生会喜欢看的
【在 t******g 的大作中提到】
: 男的太英俊了， 有点太太英俊了， 呵呵， 女生会喜欢看的
X*r
12 楼
No, this understanding is wrong.
If you declare 'char a[10];', 'a' has type 'char [10]', and '&a' has
type 'char (*)[10]'.
If you declare 'char *b;', 'b' has type 'char *', and '&b' has type
'char **'.
Type 'char []' can be implicitly converted into type 'char *', so 'a'
can be used in almost everywhere 'char *' is required. However,
'char (*)[]' cannot be converted to 'char **', so your code won't work.
which
【在 c*******9 的大作中提到】
: I think a is name of an array of char, so a is pointer to the a[0], which
: should be of type char*, is that correct?
: if so &a should be of type char** ?
: thanks...
If you declare 'char a[10];', 'a' has type 'char [10]', and '&a' has
type 'char (*)[10]'.
If you declare 'char *b;', 'b' has type 'char *', and '&b' has type
'char **'.
Type 'char []' can be implicitly converted into type 'char *', so 'a'
can be used in almost everywhere 'char *' is required. However,
'char (*)[]' cannot be converted to 'char **', so your code won't work.
which
【在 c*******9 的大作中提到】
: I think a is name of an array of char, so a is pointer to the a[0], which
: should be of type char*, is that correct?
: if so &a should be of type char** ?
: thanks...
s*n
13 楼
我讨厌这个主线，没劲
【在 t***u 的大作中提到】
: 凯蒂也不错
【在 t***u 的大作中提到】
: 凯蒂也不错
X*r
14 楼
What I just said is on the syntactic level.
On the semantic level, a is an array -- it contains all its elements.
It is not the same as a pointer to its first element. The latter is
'&a[0]'. For example, sizeof(a) is 10, which is the length of the array
times size of its individual element; while sizeof(&a[0]) is 4 on
32-bit architecture, which is the size of a 'char *' pointer.
Back to your problem: 'f' requires a 'char ** input'. Now assuming
you could just pass '&a' in. What would happen if f
【在 c*******9 的大作中提到】
: I think a is name of an array of char, so a is pointer to the a[0], which
: should be of type char*, is that correct?
: if so &a should be of type char** ?
: thanks...
On the semantic level, a is an array -- it contains all its elements.
It is not the same as a pointer to its first element. The latter is
'&a[0]'. For example, sizeof(a) is 10, which is the length of the array
times size of its individual element; while sizeof(&a[0]) is 4 on
32-bit architecture, which is the size of a 'char *' pointer.
Back to your problem: 'f' requires a 'char ** input'. Now assuming
you could just pass '&a' in. What would happen if f
【在 c*******9 的大作中提到】
: I think a is name of an array of char, so a is pointer to the a[0], which
: should be of type char*, is that correct?
: if so &a should be of type char** ?
: thanks...
t*g
15 楼
不是我的茶
hehe
【在 t***u 的大作中提到】
: 凯蒂也不错
hehe
【在 t***u 的大作中提到】
: 凯蒂也不错
c*9
16 楼
Thank you Xentar...
is the following OK and safe, is strcpy potentially wiping out existing data
(the memory after a)?
char* a:
strcpy( a, anotherstring.c_str());
f( &a );
all I want to do here is to pass a char** that point to a copy of value
anotherstring.c_str()...
what is the best way to do it?
Thanks again.
is the following OK and safe, is strcpy potentially wiping out existing data
(the memory after a)?
char* a:
strcpy( a, anotherstring.c_str());
f( &a );
all I want to do here is to pass a char** that point to a copy of value
anotherstring.c_str()...
what is the best way to do it?
Thanks again.
c*4
17 楼
恩，真得好看。两个男一号都不错，不同的类型。
两人之间那种若有若无的信任让人感觉很窝心。
我这个礼拜疯狂的追着。
是只出到第一季马？
两人之间那种若有若无的信任让人感觉很窝心。
我这个礼拜疯狂的追着。
是只出到第一季马？
X*r
18 楼
No, that's wrong, either, because you didn't allocate memory
for a.
What you want to do could be the following:
char a[10], *b = a;
strcpy(a, anotherstring.c_str());
f(&b);
I didn't reply with the solution immediately because I wanted you
to understand the issue.
Another unrelated reminder is that strcpy is inherently dangerous.
Unless you're 100% sure the length of anotherstring is no greater
than 9, your code is not safe. Use strncpy instead.
existing data
value
【在 c*******9 的大作中提到】
: Thank you Xentar...
: is the following OK and safe, is strcpy potentially wiping out existing data
: (the memory after a)?
: char* a:
: strcpy( a, anotherstring.c_str());
: f( &a );
: all I want to do here is to pass a char** that point to a copy of value
: anotherstring.c_str()...
: what is the best way to do it?
: Thanks again.
for a.
What you want to do could be the following:
char a[10], *b = a;
strcpy(a, anotherstring.c_str());
f(&b);
I didn't reply with the solution immediately because I wanted you
to understand the issue.
Another unrelated reminder is that strcpy is inherently dangerous.
Unless you're 100% sure the length of anotherstring is no greater
than 9, your code is not safe. Use strncpy instead.
existing data
value
【在 c*******9 的大作中提到】
: Thank you Xentar...
: is the following OK and safe, is strcpy potentially wiping out existing data
: (the memory after a)?
: char* a:
: strcpy( a, anotherstring.c_str());
: f( &a );
: all I want to do here is to pass a char** that point to a copy of value
: anotherstring.c_str()...
: what is the best way to do it?
: Thanks again.
d*g
19 楼
看了几集，老觉得年轻男主角装模作样的很假。。。可能不是我的茶
c*9
20 楼
Thanks Xenta...
will the following work also?
char a[10]:
strcpy( a, anotherstring.c_str());
f( &(&a[0]) );
will the following work also?
char a[10]:
strcpy( a, anotherstring.c_str());
f( &(&a[0]) );
h*a
21 楼
【在 c*********4 的大作中提到】
: 恩，真得好看。两个男一号都不错，不同的类型。
: 两人之间那种若有若无的信任让人感觉很窝心。
: 我这个礼拜疯狂的追着。
: 是只出到第一季马？
p*o
22 楼
Get a C book. You won't learn C from BBS.
BTW, the function f(char **p) looks quite suspicious.
It sounds to me it want to do some tricky things like
freeing *p following by allocating another buffer and
passing it outside, pretty much realloc. It will get
into serious problem if you pass in an array in this
case.
【在 c*******9 的大作中提到】
: Thanks Xenta...
: will the following work also?
: char a[10]:
: strcpy( a, anotherstring.c_str());
: f( &(&a[0]) );
BTW, the function f(char **p) looks quite suspicious.
It sounds to me it want to do some tricky things like
freeing *p following by allocating another buffer and
passing it outside, pretty much realloc. It will get
into serious problem if you pass in an array in this
case.
【在 c*******9 的大作中提到】
: Thanks Xenta...
: will the following work also?
: char a[10]:
: strcpy( a, anotherstring.c_str());
: f( &(&a[0]) );
r*x
23 楼
Did anyone see last night's season finale? It seemed pretty obvious Kate
didn't stay on that plane
didn't stay on that plane
X*r
24 楼
No. &a[0] is not a lvalue itself, so you cannot take its address.
【在 c*******9 的大作中提到】
: Thanks Xenta...
: will the following work also?
: char a[10]:
: strcpy( a, anotherstring.c_str());
: f( &(&a[0]) );
【在 c*******9 的大作中提到】
: Thanks Xenta...
: will the following work also?
: char a[10]:
: strcpy( a, anotherstring.c_str());
: f( &(&a[0]) );
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