新的DACD Feb 18就生效了,h4还是遥遥无期 KAO USCIS @USCIS 8h8 hours ago Alert: Expanded DACA program launches February 18, 2015. Details at http://uscis.gov/immigrationaction#daca …
【在 a*0 的大作中提到】 : 新的DACD Feb 18就生效了,h4还是遥遥无期 : KAO : USCIS @USCIS 8h8 hours ago : Alert: Expanded DACA program launches February 18, 2015. Details at http://uscis.gov/immigrationaction#daca …
h*9
11 楼
拍脑袋想出了这个办法: 从头到尾扫一遍: 1. 如果碰到连续的负数,将其合并; 2. 如果碰到连续的正数,将其合并; 3. 然后 while (a[i-2] + a[i-1] > 0 && a[i] + a[i-1] > 0) { 合并 a[i-2],a[i-1],a[i]; i = i - 2; } 4. move on to next item and repeat the same sequence.
Seems old question. Am I right? Scan from head to tail add if current sum is still positive Update max sum if possible. Once current sum is below zero, remove former part until it is positive again.
o*r
18 楼
支持,推了
s*o
19 楼
thanks for the info, did it yesterday, and did it just now twice!