Question: "-" operators: z= -x; z = x-y - 未名空间MITBBS历史存档

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Question: "-" operators: z= -x; z = x-y

Question: "-" operators: z= -x; z = x-y# DotNet - 窗口里的风景

f*l2003-11-05 08:11

1 楼

the operator "-" in
z= -x
and
z= x-y
are two different things, how to define them to make a difference?

f*l2003-11-05 08:11

2 楼

found this: one operand or 2 operands will make the difference.
z= -x:
public operator-(Complex opr1)
{
return new Complex(-opr1.real, -opr1.imag);
}
public operator-(Complex opr1, Complex opr2)
{
return new Complex(opr1.real-opr2.real, opr1.imag-opr2.imag);
}

【在 f******l 的大作中提到】

: the operator "-" in
: z= -x
: and
: z= x-y
: are two different things, how to define them to make a difference?