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String::Format doesn't take integer type params

String::Format doesn't take integer type params# DotNet - 窗口里的风景

P*s2005-07-11 07:07

1 楼

Here is the code snippet ( managed C++)
...
Int32 nTemp = 10;
String * pMsg = String::Format("Display an integer here: {0}", nTemp);
...
I got an error message when tried to compile the program:
error C2665: 'System::String::Format' : none of the 5 overloads can convert pa
rameter 2 from type 'int'
Am I missing anything here? Thanx in advance.

r*y2005-07-11 07:07

2 楼

nTemp.ToString()
then ok

【在 P********s 的大作中提到】

: Here is the code snippet ( managed C++)
: ...
: Int32 nTemp = 10;
: String * pMsg = String::Format("Display an integer here: {0}", nTemp);
: ...
: I got an error message when tried to compile the program:
: error C2665: 'System::String::Format' : none of the 5 overloads can convert pa
: rameter 2 from type 'int'
: Am I missing anything here? Thanx in advance.

P*s2005-07-11 07:07

3 楼

Thanks for the reply. I also found another solution:
String::Format("....", __box(nTemp));
The __box() keyword wraps the integer as an object.

nTemp.ToString
()
then ok

【在 r****y 的大作中提到】

:
: nTemp.ToString()
: then ok