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How to get a matched String?

How to get a matched String?# Java - 爪哇娇娃

g*g2008-08-08 07:08

1 楼

If you have a long text, you want to use regex to match it and
get back the first matched String, is this what I should do?
String[] strs = text.split("regex", 2);
text.substring(strs[0].length, text.length - strs[1].length);

t*e2008-08-08 07:08

2 楼

try Pattern and Matcher classes.

m*t2008-08-08 07:08

3 楼

But that only gets you the part _before_ the first matching substring.
Try something like Pattern.compile(regex).matcher(text).find()

【在 g*****g 的大作中提到】

: If you have a long text, you want to use regex to match it and
: get back the first matched String, is this what I should do?
: String[] strs = text.split("regex", 2);
: text.substring(strs[0].length, text.length - strs[1].length);

g*g2008-08-08 07:08

4 楼

Actually this should work, coz str[0] is the part before, and
str[1] is the part after. But your way looks more elegant.

【在 m******t 的大作中提到】

:
: But that only gets you the part _before_ the first matching substring.
: Try something like Pattern.compile(regex).matcher(text).find()

m*t2008-08-08 07:08

5 楼

Oh, right, now that I read it again, the index jumping makes
sense.
...Yeah... I guess that shows the pattern approach _is_ at least
more readable. ;-)

【在 g*****g 的大作中提到】

: Actually this should work, coz str[0] is the part before, and
: str[1] is the part after. But your way looks more elegant.