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math expression

math expression# Java - 爪哇娇娃

w*r2009-07-15 07:07

1 楼

需要用一个简单的math expression parser。类似于做：
f(x1, x2,... xn) = (a1x1 + x2 *x3)*a2 -x4 ..
基本上都是四则运算。有没有什么open source的上手就可以用的library？谢谢！

m*t2009-07-15 07:07

2 楼

antlr? It's fairly straightfoward.

【在 w*r 的大作中提到】

: 需要用一个简单的math expression parser。类似于做：
: f(x1, x2,... xn) = (a1x1 + x2 *x3)*a2 -x4 ..
: 基本上都是四则运算。有没有什么open source的上手就可以用的library？谢谢！

F*n2009-07-15 07:07

3 楼

Why not use Rhino, hoho.

【在 m******t 的大作中提到】

:
: antlr? It's fairly straightfoward.

c*t2009-07-15 07:07

4 楼

No need to use antlr. My CookCC is smaller, faster and better :)
In fact, operator precedence is the worst nightmare for LL parsers
such as antlr.
CookCC even comes with a calculator example (well, a mini script
interpreter of a few hundred lines) that you just need to do minor
modifcations:
http://code.google.com/p/cookcc/source/browse/trunk/tests/javaap/calc/Calculator.java

【在 m******t 的大作中提到】

:
: antlr? It's fairly straightfoward.

w*r2009-07-15 07:07

5 楼

thanks!
永远向唐僧大师学习!

【在 c*****t 的大作中提到】

: No need to use antlr. My CookCC is smaller, faster and better :)
: In fact, operator precedence is the worst nightmare for LL parsers
: such as antlr.
: CookCC even comes with a calculator example (well, a mini script
: interpreter of a few hundred lines) that you just need to do minor
: modifcations:
: http://code.google.com/p/cookcc/source/browse/trunk/tests/javaap/calc/Calculator.java