【在 i**********e 的大作中提到】 : a trick using pointer arithmetic. : (int)((int*)0+1) : 一些常见面试题的答案与总结 - : http://www.ihas1337code.com
z*i
6 楼
membership fee?
【在 S*********t 的大作中提到】 : Angie's list : serviceMagic.com charges too much.
i*e
7 楼
First, advance the pointer at address 0 by one. How many it advances depend on the size of the pointer type. 一些常见面试题的答案与总结 - http://www.ihas1337code.com
V*T
8 楼
On the contrary,the contractor from Servicemagic charges much less than those from Angie's list. We canceled Angie's list membership and started to use servicemagic more.
【在 S*********t 的大作中提到】 : Angie's list : serviceMagic.com charges too much.
y*e
9 楼
这个方法很妙!
depend
【在 i**********e 的大作中提到】 : First, advance the pointer at address 0 by one. How many it advances depend : on the size of the pointer type. : 一些常见面试题的答案与总结 - : http://www.ihas1337code.com
V*T
10 楼
servicemagic is free Angie's list charges annual fee.
【在 z**********i 的大作中提到】 : membership fee?
c*2
11 楼
There are at least two other ways: 1) int a[2]; unsigned addr0=&a[0]; unsigned addr1=&a[1]; size_t sizeofint=addr1-addr0; 2) typedef struct ab { int a; int b; } AB; sizeofint=offset(b in AB) =(unsigned)(&((AB*)0->b))
I*M
12 楼
Our experience with ServiceMagic is pretty good.
m*1
13 楼
contractors have to pay ServiceMagic $40-50 to get job information if they want to come to your house to see the job.