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沧海笑# Piebridge - 鹊桥

p*e2011-07-29 07:07

1 楼

【以下文字转载自 FleaMarket 讨论区】
发信人: pixie (pixie), 信区: FleaMarket
标题: 寄点维生素和非处方药回国，怎么寄比较好？
发信站: BBS 未名空间站 (Tue Feb 15 23:44:53 2011, 美东)
请教。有关税么？
有包子。

k*r2011-07-29 07:07

2 楼

function double sqrt(double d, int p). p is precision option. My code is as
follows. Please let me know if you see any error. Thanks,
public static double sqrt(double d, int p) {
if (d < 0) {
return Double.NaN;
}
double prec = Math.pow(10, - p);
double start = 0;
double end = d;
while (start < end) {
double mid = start + (end - start) / 2;
if (mid == 0) {
return mid;
}
if (mid * mid == d) {
return mid;
} else if (mid < d / mid) {
start = mid + prec;
} else {
end = mid - prec;
}
}
return start;
}

s*y2011-07-29 07:07

3 楼

生完快5天了，在医院的头2天，宝宝吸奶很有力，每次吸不停，可是就一点初乳，压根
没吃到啥，还得
喂很多医院的液体奶。
现在的情况，开始电动泵奶2天，每天就2，3次。实在太累，每次1小时多，就80-100cc
左右。
请问过来的妈妈们，奈良算正常吗？
给宝宝胸喂，能吸饱吗？泵出来喂，是不好一点？什么时候可以大量产奶啊？头一周
什么汤催奶最好
呢？
新妈求教，谢谢！

r*w2011-07-29 07:07

4 楼

粤语版

k*r2011-07-29 07:07

5 楼

求教有人帮忙看看吗

s*x2011-07-29 07:07

6 楼

for most of interview codes, if you have more than 10 lines, usually
something wrong.
1) for number less than 1 and great than one, it should be processed
differently.
2) why you need to check mid == 0?
3) why you need add prec to mid each time?
4) always compare with a precision for floats, do not compare directly.

k*r2011-07-29 07:07

7 楼

大牛能否写个clean的code供学习一下。

【在 s**x 的大作中提到】

: for most of interview codes, if you have more than 10 lines, usually
: something wrong.
: 1) for number less than 1 and great than one, it should be processed
: differently.
: 2) why you need to check mid == 0?
: 3) why you need add prec to mid each time?
: 4) always compare with a precision for floats, do not compare directly.

s*x2011-07-29 07:07

8 楼

google.

【在 k****r 的大作中提到】

: 大牛能否写个clean的code供学习一下。

k*r2011-07-29 07:07

9 楼

你太牛了

【在 s**x 的大作中提到】

:
: google.

D*a2011-07-29 07:07

10 楼

you code is wrong by checking "mid * mid == d"
you should return mid if abs(start-end)
as

【在 k****r 的大作中提到】

: function double sqrt(double d, int p). p is precision option. My code is as
: follows. Please let me know if you see any error. Thanks,
: public static double sqrt(double d, int p) {
: if (d < 0) {
: return Double.NaN;
: }
: double prec = Math.pow(10, - p);
: double start = 0;
: double end = d;
: while (start < end) {

k*r2011-07-29 07:07

11 楼

right. Thanks for the hint.

【在 D*******a 的大作中提到】

: you code is wrong by checking "mid * mid == d"
: you should return mid if abs(start-end):
: as

s*x2011-07-29 07:07

12 楼

if ( d < 0) return -1;
prec = ...;
start = d > 1 ? 1: d;
end = d > 1 ? d : 1;
While(1) {
m = (start + end) / 2;
v = m * m - d;
if(v > prec)
end = m;
else if( v < -prec)
start = m;
else
return m;
}
}

N*m2011-07-29 07:07

13 楼

newton's method

as

【在 k****r 的大作中提到】

k*r2011-07-29 07:07

14 楼

thank you for the sharing. much more clear now.

【在 s**x 的大作中提到】

: if ( d < 0) return -1;
: prec = ...;
: start = d > 1 ? 1: d;
: end = d > 1 ? d : 1;
: While(1) {
: m = (start + end) / 2;
: v = m * m - d;
: if(v > prec)
: end = m;
: else if( v < -prec)