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如何显示出“*”

如何显示出“*”# Unix - 噫吁兮，危乎高哉

u*n2001-02-23 08:02

1 楼

如果进行下面一步操作：
set a = "*"
echo $a
则将会出现该目录下所有文件名，而如何能将“*”本身赋值
给变量a，使echo $a显示的只是“*”，HOW TO DO THAT ?

m*e2001-02-23 08:02

2 楼

set a="'*'"

【在 u*******n 的大作中提到】

: 如果进行下面一步操作：
: set a = "*"
: echo $a
: 则将会出现该目录下所有文件名，而如何能将“*”本身赋值
: 给变量a，使echo $a显示的只是“*”，HOW TO DO THAT ?

u*n2001-02-23 08:02

3 楼

spitfire 116: set a="'*'"
spitfire 117: echo $a
echo: No match

【在 m*****e 的大作中提到】

: set a="'*'"

d*g2001-02-23 08:02

4 楼

that's easy:
set a = '*'
(or set a = "*" )
echo "$a" <======= with " "
will display as:
*

【在 u*******n 的大作中提到】

:
: spitfire 116: set a="'*'"
: spitfire 117: echo $a
: echo: No match

u*n2001-02-23 08:02

5 楼

hehe....
I want "echo $a" ----> *
Not just echo "*"----> *
如何能将“*”本身赋值给变量a，使echo $a显示的只是“*” ?

【在 d*****g 的大作中提到】

: that's easy:
: set a = '*'
: (or set a = "*" )
: echo "$a" <======= with " "
: will display as:
: *

c*t2001-02-23 08:02

6 楼

Your question is unclear.

【在 u*******n 的大作中提到】

: hehe....
: I want "echo $a" ----> *
: Not just echo "*"----> *
: 如何能将“*”本身赋值给变量a，使echo $a显示的只是“*” ?

d*g2001-02-23 08:02

7 楼

hehe, I don't understand what you mean.....
You need to learn some basic of UNIX SHELLL ...
Please first learn the difference for following commands:
set a = "*" NOTE: please don't use: set a = *
1) echo $a
2) echo "$a"
I have to point out:
set a = '*'
set a = *
set a = "*"
are not the same.
if you use set a = *
you will always set a as current directory's files, not
character * ....
only use set a ='*' or set a ="*", just asign character * to
a
have you tried 2)?? it will j

【在 u*******n 的大作中提到】

: hehe....
: I want "echo $a" ----> *
: Not just echo "*"----> *
: 如何能将“*”本身赋值给变量a，使echo $a显示的只是“*” ?