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regexp help

regexp help# Unix - 噫吁兮，危乎高哉

F*e2003-02-20 08:02

1 楼

what's the regular expression for "not contaning colon", for which
the following will return 1:
aabbcc
and the following will return 0:
aabb:cc
Thanks.

w*g2003-02-20 08:02

2 楼

/[^:]/g, well, following perl convention.

【在 F**e 的大作中提到】

: what's the regular expression for "not contaning colon", for which
: the following will return 1:
: aabbcc
: and the following will return 0:
: aabb:cc
: Thanks.

o*z2003-02-20 08:02

3 楼

把match "containing colon"的结果反一下成不?

【在 F**e 的大作中提到】

: what's the regular expression for "not contaning colon", for which
: the following will return 1:
: aabbcc
: and the following will return 0:
: aabb:cc
: Thanks.

F*e2003-02-20 08:02

4 楼

How to invert?
"match colon" would be "[:]", but "[^:]" returns 1 in both cases.

【在 o***z 的大作中提到】

: 把match "containing colon"的结果反一下成不?

p*f2003-02-20 08:02

5 楼

if perl, you can say,
$_ !~ /:/;
or
$_ =~ /^[^:]*$/;

【在 F**e 的大作中提到】

: what's the regular expression for "not contaning colon", for which
: the following will return 1:
: aabbcc
: and the following will return 0:
: aabb:cc
: Thanks.

o*z2003-02-20 08:02

6 楼

change 'if' to 'unless'?

【在 F**e 的大作中提到】

: How to invert?
: "match colon" would be "[:]", but "[^:]" returns 1 in both cases.