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急问: 教教我这小小scrip错哪了?

急问: 教教我这小小scrip错哪了?# Unix - 噫吁兮，危乎高哉

w*e2004-05-05 07:05

1 楼

我不明白为什么变量path 不能带到ls命令中
#!/bin/csh -f
set path=./cs111b
ls -l $path
echo path=$path
libra% aa
ls: Command not found
path=./cs111b
可以马上回答吗? 谢谢

x*g2004-05-05 07:05

2 楼

After you set path to a new value, ls cannot be found there.
You need to either include the path where ls locates to path variable,
or prefix ls with path.

【在 w**********e 的大作中提到】

: 我不明白为什么变量path 不能带到ls命令中
: #!/bin/csh -f
: set path=./cs111b
: ls -l $path
: echo path=$path
: libra% aa
: ls: Command not found
: path=./cs111b
: 可以马上回答吗? 谢谢

m*e2004-05-05 07:05

3 楼

it is "Command" not found, not "path" not found.
try a different variable name from "path".
$path turns out to be used by shell to find all "Command"s,
therefore if you set it to ./cs111b, all you can execute are
shell build-ins plus executables in ./cs111b/ only.

【在 x******g 的大作中提到】

: After you set path to a new value, ls cannot be found there.
: You need to either include the path where ls locates to path variable,
: or prefix ls with path.