How to generate a series number which falls in a specified discrete probability distribution? thx
c*e
2 楼
map
【在 t*****r 的大作中提到】 : How to generate a series number which falls in a specified discrete : probability distribution? : thx
t*r
3 楼
details? or an example? thx
【在 c*******e 的大作中提到】 : map
s*l
4 楼
You can look at 'numerical recipe'. It's even got fortran and C codes.
【在 t*****r 的大作中提到】 : details? : or an example? : thx
e*c
5 楼
Assume you can generate U(0,1) distribution, then the discrete prob distribution with following dist: P{X=xi}=pi can be generated by dividing the interval [0,1] with subdivisions [0,p1), [p1,p1+p2), [p1+p2,p1+p2+p3),...[p1+...+p(n-1),1] and for X~U(0,1), if X falls into [0,p1) then make X=x1, clearly this has prob. p1; if X falls into [p1,p1+p2), then make X=x2, clearly this has prob. p2; and so on...
【在 t*****r 的大作中提到】 : How to generate a series number which falls in a specified discrete : probability distribution? : thx