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j*1
7 楼
Thank you!
p*k
8 楼
1. (4n-2)/n^2; 2. Fibonacci number + n; 3. x[n+1]=x[n]^x[n-1] for n>=2; 4. x[n+1]=2*x[n]-x[n-1]+(-2)^(n-1) for n>=2, x[n] = 21 + [2+(-2)^n]/9 + 19(n-1)/3; 5. x[n+1]=n^2-x[n]-x[n-1] for n>=2.
l*g
9 楼
牛人!
【在 p*****k 的大作中提到】 : 1. (4n-2)/n^2; : 2. Fibonacci number + n; : 3. x[n+1]=x[n]^x[n-1] for n>=2; : 4. x[n+1]=2*x[n]-x[n-1]+(-2)^(n-1) for n>=2, : x[n] = 21 + [2+(-2)^n]/9 + 19(n-1)/3; : 5. x[n+1]=n^2-x[n]-x[n-1] for n>=2.