Nyquist关于maximum data rate的theorem < 2 * H * n where H is the bandwidth of noiseless channel n is the number of bits for each signal 由于 data rate = baud * n 所以他只是给出了 baud 的上限, baud < 2 * H 至于 maximum data rate, 好像没有啊,n 不是可以随意的么? It sounds stupid. But I want to know.
【在 z*y 的大作中提到】 : Nyquist关于maximum data rate的theorem : < 2 * H * n : where H is the bandwidth of noiseless channel : n is the number of bits for each signal : 由于 data rate = baud * n : 所以他只是给出了 baud 的上限, baud < 2 * H : 至于 maximum data rate, 好像没有啊,n 不是可以随意的么? : It sounds stupid. But I want to know.
yeah, n is only related to signal not medium 所以,只知道bandwidth是不能确定maximum data rate, right? I can achieve as large data rate as I want by choosing different signals, right?