Base requirements, like degree, years of experience must be same or higher. Job function differences must be less than 50%. Salary must be equal or higher.
d*c
12 楼
人家的翅膀是放喷气口的,不是扇乎的
s*8
13 楼
买台旧的 二三十万 回去捐给学校 免关税
【在 g********r 的大作中提到】 : 买一台,运回国去
h*t
14 楼
Assuming the poles of the OpAmp and 1/(Cload*Rd) are located at high frequency, then 3db bandwidth of the circuit you are showing is determined by R and C of the node vx. if you ignore cp, (assume cp is 0), the output resistance looking into vx is 1/((1+A)*gm). Capacitance load is C2. pole = 1/RC=(1+A)gm/C2 Note: if we ignore Cp, the equivalent load capacitance to Vx is C2 only. The reason is simple. if you apply at test current source at vx, the current won't go to C1, because it is assumed Isig has infinite output impedance. So , C1 does not load Vx node. what if we must include Cp? Then C1 and Cp will also load Vx. the output resistance looking into vx is (C1+Cp)/C1 *[1/((1+A)*gm)]. This is because Cp reduces the loop gain by a factor of (C1+Cp)/C1 , so output resistance increases by a factor of (C1+Cp)/C1 . capacitive load at vx becomes C2 + C1*Cp/(C1+Cp) 3db pole = 1/RC=(1+A)gm/[(C1C2+C1Cp+C2Cp)/C1] if Cp -->0, it becomes (1+A)gm/C2
【在 n***s 的大作中提到】 : Base requirements, like degree, years of experience must be same or higher. : Job function differences must be less than 50%. Salary must be equal or : higher.
m*e
18 楼
那说有三个A*hole还差不多
【在 d******c 的大作中提到】 : 人家的翅膀是放喷气口的,不是扇乎的
g*r
19 楼
你的说的是, 20-30万美元吗?
【在 s**********8 的大作中提到】 : 买台旧的 二三十万 回去捐给学校 免关税
m*a
20 楼
谢谢大牛,包子已发:)
determined is The So
【在 h********t 的大作中提到】 : Assuming the poles of the OpAmp and 1/(Cload*Rd) are located at high : frequency, then 3db bandwidth of the circuit you are showing is determined : by R and C of the node vx. : if you ignore cp, (assume cp is 0), the output resistance looking into vx is : 1/((1+A)*gm). Capacitance load is C2. pole = 1/RC=(1+A)gm/C2 : Note: if we ignore Cp, the equivalent load capacitance to Vx is C2 only. The : reason is simple. if you apply at test current source at vx, the current : won't go to C1, because it is assumed Isig has infinite output impedance. So : , C1 does not load Vx node. : what if we must include Cp? Then C1 and Cp will also load Vx.
j*r
21 楼
Maybe both BS41 and BS21,都是你害的吧,呵呵.估计最后版上人手一套.我的还没拆呢.
那当然了,organic listing永远是trump ppc listing的。因为用户对自然排名的链接 更加信任。这个有人做过试验,确认的。具体的效用比率不清楚了。 哈哈,如果你crack了Google的算法,那你就是奇功一件啦。 说是没有人能crack Google的算法,但还是有很多人从不同的方面部分的reverse engineer了G的算法。其实,机器就是dumb的。这年头,computer science还没有发展 到AI走向彻底实用的阶段。 如果你想继续保持SEO的高性价比,我看只有多投入精力,钱等。罗马不是一天建成的 ,result will come, when you are ready for it.
那当然了,organic listing永远是trump ppc listing的。因为用户对自然排名的链接 更加信任。这个有人做过试验,确认的。具体的效用比率不清楚了。 哈哈,如果你crack了Google的算法,那你就是奇功一件啦。 说是没有人能crack Google的算法,但还是有很多人从不同的方面部分的reverse engineer了G的算法。其实,机器就是dumb的。这年头,computer science还没有发展 到AI走向彻底实用的阶段。 如果你想继续保持SEO的高性价比,我看只有多投入精力,钱等。罗马不是一天建成的 ,result will come, when you are ready for it.
【在 g********r 的大作中提到】 : 310-MS LC/MS from Varian? : The linear footprint of the 310-MS is one of the smallest of any triple quad : LC/MS – under 72 centimeters (28 inches).