immutable list# Java - 爪哇娇娃
p*p
1 楼
I have writen some config data in a List and have to immutable reference,
how? or create a clone copy?
how? or create a clone copy?
g*g
2 楼
You can have your list as a field in another class,
say ImmutableList, and in this class you only expose
method that you want to expose. e.g. only the get(int i)
class ImmutableList {
private List data;
public Object get(int i) {
return data.get(i);
}
}
【在 p***p 的大作中提到】
: I have writen some config data in a List and have to immutable reference,
: how? or create a clone copy?
say ImmutableList, and in this class you only expose
method that you want to expose. e.g. only the get(int i)
class ImmutableList {
private List data;
public Object get(int i) {
return data.get(i);
}
}
【在 p***p 的大作中提到】
: I have writen some config data in a List and have to immutable reference,
: how? or create a clone copy?
p*p
3 楼
Well, I have to reture a List
object, so any suggestion?
【在 g*****g 的大作中提到】
: You can have your list as a field in another class,
: say ImmutableList, and in this class you only expose
: method that you want to expose. e.g. only the get(int i)
: class ImmutableList {
: private List data;
: public Object get(int i) {
: return data.get(i);
: }
: }
object, so any suggestion?
【在 g*****g 的大作中提到】
: You can have your list as a field in another class,
: say ImmutableList, and in this class you only expose
: method that you want to expose. e.g. only the get(int i)
: class ImmutableList {
: private List data;
: public Object get(int i) {
: return data.get(i);
: }
: }
g*g
4 楼
这个建议不加，因为是要只读的，一旦实现List,那些add/remove方法都要实现，
固然可以实现为空方法或抛异常，但都不如编译时就告诉你这个方法没有。
不过可以先定义一个ImmutableListInterface。
【在 p***p 的大作中提到】
: Well, I have to reture a List
: object, so any suggestion?
固然可以实现为空方法或抛异常，但都不如编译时就告诉你这个方法没有。
不过可以先定义一个ImmutableListInterface。
【在 p***p 的大作中提到】
: Well, I have to reture a List
: object, so any suggestion?
p*p
5 楼
是不是还加个implements?
还是extends ArrayList，然后再overload
class ImmutableList implements List{
private List data;
public Object get(int i) {
return data.get(i);
}
}
【在 g*****g 的大作中提到】
: You can have your list as a field in another class,
: say ImmutableList, and in this class you only expose
: method that you want to expose. e.g. only the get(int i)
: class ImmutableList {
: private List data;
: public Object get(int i) {
: return data.get(i);
: }
: }
还是extends ArrayList，然后再overload
class ImmutableList implements List{
private List data;
public Object get(int i) {
return data.get(i);
}
}
【在 g*****g 的大作中提到】
: You can have your list as a field in another class,
: say ImmutableList, and in this class you only expose
: method that you want to expose. e.g. only the get(int i)
: class ImmutableList {
: private List data;
: public Object get(int i) {
: return data.get(i);
: }
: }
m*y
6 楼
Collections.unmodifiableList(List list)
【在 p***p 的大作中提到】
: I have writen some config data in a List and have to immutable reference,
: how? or create a clone copy?
【在 p***p 的大作中提到】
: I have writen some config data in a List and have to immutable reference,
: how? or create a clone copy?
r*l
7 楼
嘿嘿，这是用java的人给出的答案。前面的几个回答不错，但是因为java已经实现了，
就用不着费力气了。
【在 m******y 的大作中提到】
: Collections.unmodifiableList(List list)
就用不着费力气了。
【在 m******y 的大作中提到】
: Collections.unmodifiableList(List list)
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