b*c
2 楼
人家连数字都不说……谁会知道多少chance...之前大家还估计不会超过10万呢，现在
看来没办法估计啊
看来没办法估计啊
g*u
3 楼
Take the numbers in 2008 as prior:
Reg: 131800, Adv 31200;
Given this year's total petition number is 124000, Adv # is 23735
This year's Adv chance should be
( Adv # - 20000)*(65000/(124000-20000)) + 20000)/ Adv #
which is about 94.1%.
Correct me if I am wrong.
Reg: 131800, Adv 31200;
Given this year's total petition number is 124000, Adv # is 23735
This year's Adv chance should be
( Adv # - 20000)*(65000/(124000-20000)) + 20000)/ Adv #
which is about 94.1%.
Correct me if I am wrong.
r*s
4 楼
p = 1-(1-20000/x)*(1-65000/104000)
x是adv的总数
x是adv的总数
m*u
5 楼
时代不同了，那时候没有那么多的自费master
【在 g******u 的大作中提到】
: Take the numbers in 2008 as prior:
: Reg: 131800, Adv 31200;
: Given this year's total petition number is 124000, Adv # is 23735
: This year's Adv chance should be
: ( Adv # - 20000)*(65000/(124000-20000)) + 20000)/ Adv #
: which is about 94.1%.
: Correct me if I am wrong.
【在 g******u 的大作中提到】
: Take the numbers in 2008 as prior:
: Reg: 131800, Adv 31200;
: Given this year's total petition number is 124000, Adv # is 23735
: This year's Adv chance should be
: ( Adv # - 20000)*(65000/(124000-20000)) + 20000)/ Adv #
: which is about 94.1%.
: Correct me if I am wrong.
k*e
6 楼
probability不错，发offer一枚，签证需要到火星面签
【在 g******u 的大作中提到】
: Take the numbers in 2008 as prior:
: Reg: 131800, Adv 31200;
: Given this year's total petition number is 124000, Adv # is 23735
: This year's Adv chance should be
: ( Adv # - 20000)*(65000/(124000-20000)) + 20000)/ Adv #
: which is about 94.1%.
: Correct me if I am wrong.
【在 g******u 的大作中提到】
: Take the numbers in 2008 as prior:
: Reg: 131800, Adv 31200;
: Given this year's total petition number is 124000, Adv # is 23735
: This year's Adv chance should be
: ( Adv # - 20000)*(65000/(124000-20000)) + 20000)/ Adv #
: which is about 94.1%.
: Correct me if I am wrong.
l*c
7 楼
advanced应该至少有80％的概率，假设和总体的比例差不多为1比2的话。
g*u
8 楼
Right, the two methods come to the same result: 94.1%, assuming the same
percentage of Adv as in 2008.
【在 r*****s 的大作中提到】
: p = 1-(1-20000/x)*(1-65000/104000)
: x是adv的总数
percentage of Adv as in 2008.
【在 r*****s 的大作中提到】
: p = 1-(1-20000/x)*(1-65000/104000)
: x是adv的总数
相关阅读
【请教】什么时候开始找毕业年的CO-OP实习?请教Data Engineering 和Data Science and Engineering 的区别walmartlab面经面试中“WHAT"S YOUR WEAKNESS?”怎么回答?问道面试题Amazon家manager的级别根SDEIII一样么?谁能帮解读一下offer letter这个term?问一个关于跳槽到甲方的问题leetcode online judge有参考答案么求同学们帮忙提供信息 opt volunteer挂靠如何在面试中写出好的代码？（一）[合集] 有投过GE global research的前辈么？leetcode combinationsum2 超时像这种面试题应该如何思考和回答呢？ (转载)有必要将O1签证转成H1B签证吗？[请教]h1b的申请与eb1b的关系 (转载)帮着看到G家题问个关于BB的问题面试结束老板主动给名片Leetcode problems' difficulty