$2的防强奸装置诞生啦# Joke - 肚皮舞运动
i*t
1 楼
输入是一个字符串,然后判断这个字符串是不是26个字母都出现了,并打印出没有出现的
字母
万分感谢
char *getMissingLetters(const char *sentence){
int len;
char * ret;
int i, index = 0;
int marker[26]; //remember how many time char occurs in the string
if(sentence == NULL)
return "";
ret = (char*)malloc(sizeof(char)*26); //malloc buffer for return
string
if(ret == NULL) //malloc fail
return "";
len = strlen(sentence); //get string length
for(i = 0; i < 26
字母
万分感谢
char *getMissingLetters(const char *sentence){
int len;
char * ret;
int i, index = 0;
int marker[26]; //remember how many time char occurs in the string
if(sentence == NULL)
return "";
ret = (char*)malloc(sizeof(char)*26); //malloc buffer for return
string
if(ret == NULL) //malloc fail
return "";
len = strlen(sentence); //get string length
for(i = 0; i < 26
