刀枪不入的喵星人# Joke - 肚皮舞运动
t*s
1 楼
能不能自动自动换行啊,一个很长的方程,比如下面这一个,有包子好伐
\noindent\(\frac{1}{2 \gamma \sigma _1 \sqrt{1-\rho _{2,1}^2}}\left(2 (r-\m
athbf{v}) (-1+\gamma ) \sqrt{1-\rho _{2,1}^2} \left(\sigma _4 \rho _{4,1}
g_{\gamma }{}^{(0,0,0,0,1)}[t,S,\mathbf{v},r,\mathbb{D}]+\sigma _3 \rho _{3,
1} g_{\gamma }{}^{(0,0,0,1,0)}[t,S,\mathbf{v},r,\mathbb{D}]+\sigma _2
\rho _{2,1} g_{\gamma }{}^{(0,0,1,0,0)}[t,S,\mathbf{v},r,\mathbb{D}]\right)+
2 S \sigma _1^2 \sqrt{1-\rho _{2,1}^2} \left(\sigma _4 \rho _{4,1} \left(g_{
\gamma
}{}^{(0,
\noindent\(\frac{1}{2 \gamma \sigma _1 \sqrt{1-\rho _{2,1}^2}}\left(2 (r-\m
athbf{v}) (-1+\gamma ) \sqrt{1-\rho _{2,1}^2} \left(\sigma _4 \rho _{4,1}
g_{\gamma }{}^{(0,0,0,0,1)}[t,S,\mathbf{v},r,\mathbb{D}]+\sigma _3 \rho _{3,
1} g_{\gamma }{}^{(0,0,0,1,0)}[t,S,\mathbf{v},r,\mathbb{D}]+\sigma _2
\rho _{2,1} g_{\gamma }{}^{(0,0,1,0,0)}[t,S,\mathbf{v},r,\mathbb{D}]\right)+
2 S \sigma _1^2 \sqrt{1-\rho _{2,1}^2} \left(\sigma _4 \rho _{4,1} \left(g_{
\gamma
}{}^{(0,