d*a
2 楼
波涛 鋼琴曲,純音樂,輕音樂,最好聽的歌,背景音樂 ,中文流行音樂,最佳中国歌曲
A*J
3 楼
马上要做决定了。谢谢啊。房子还蛮贵的。
k*f
4 楼
有没有只需要n阶乘交换,就可以找到所有的排列的算法?
这个排列数组里面,按出现的顺序排下来,
前后两个排列只相差2个位置。
这个排列数组里面,按出现的顺序排下来,
前后两个排列只相差2个位置。
c*3
6 楼
最好不要
实在喜欢对着路修个半圆型的水池,圆形边对着路,或圆弧型墙,
尽可能有路宽
实在喜欢对着路修个半圆型的水池,圆形边对着路,或圆弧型墙,
尽可能有路宽
g*8
7 楼
123
132
312
321
231
213
right?
132
312
321
231
213
right?
A*J
9 楼
谢谢,房子退了已经
f*u
11 楼
不是免费,是合在一起交了1070刀。不管你申不申请ead,AP什么的,以前是不申请这
些不用交这么多钱的。所以,你一张支票交1070,包括了485,AP,EAD的申请费。不需
要再另交钱了。
些不用交这么多钱的。所以,你一张支票交1070,包括了485,AP,EAD的申请费。不需
要再另交钱了。
S*g
12 楼
http://mathworld.wolfram.com/Permutation.html
【在 k****f 的大作中提到】
: 有程序么??
: 手动是可以排的
【在 k****f 的大作中提到】
: 有程序么??
: 手动是可以排的
r*r
14 楼
simplest solution is via backtracking
r*t
16 楼
in what lang?
http://code.activestate.com/recipes/66463/
http://code.activestate.com/recipes/66463/
k*f
17 楼
http://marknelson.us/2002/03/01/next-permutation
next_perm产生的序列不是相差一个交换
仔细看看figure 2的第二个与第三个
需要两个交换才能做到的
next_perm产生的序列不是相差一个交换
仔细看看figure 2的第二个与第三个
需要两个交换才能做到的
b*e
18 楼
#include "stdio.h"
class Bit {
public:
int max;
int direction;
int value;
Bit* higherBit;
Bit(int max, Bit* higher);
bool inc();
void changeDirection();
};
Bit::Bit(int max, Bit* higher) {
this->max = max;
this->direction = 1;
this->value = 0;
this->higherBit = higher;
}
void Bit::changeDirection() {
this->direction = 1 - this->direction;
}
bool Bit::inc() {
switch(this->direction) {
case 1:
if (this->value < this->max) {
this->value++;
return true;
class Bit {
public:
int max;
int direction;
int value;
Bit* higherBit;
Bit(int max, Bit* higher);
bool inc();
void changeDirection();
};
Bit::Bit(int max, Bit* higher) {
this->max = max;
this->direction = 1;
this->value = 0;
this->higherBit = higher;
}
void Bit::changeDirection() {
this->direction = 1 - this->direction;
}
bool Bit::inc() {
switch(this->direction) {
case 1:
if (this->value < this->max) {
this->value++;
return true;
b*e
19 楼
这个就是传说中的九连环了。
C*n
20 楼
想了解排列大部分算法,读读下面的文章:
Permutation Generation Methods by ROBERT SEDGEWlCK
Permutation Generation Methods by ROBERT SEDGEWlCK
b*e
22 楼
I am computing permutation from the permutation number. Taking a 9-
permutation as example, the permutation number is a 8 bit number where the
first bit is 2-based, second bit is 3-base, ..., the 8th bit is 9 based.
The semantics of a permutation number is that, the value of the i_th bit
means the the number of the numbers that are smaller than i and is
positioned after i in the permutation. There is a one-to-one mapping
between permutations and permutation numbers.
Then the rest is to comput
【在 g*********8 的大作中提到】
: could you explain your algorithm? thank you.
permutation as example, the permutation number is a 8 bit number where the
first bit is 2-based, second bit is 3-base, ..., the 8th bit is 9 based.
The semantics of a permutation number is that, the value of the i_th bit
means the the number of the numbers that are smaller than i and is
positioned after i in the permutation. There is a one-to-one mapping
between permutations and permutation numbers.
Then the rest is to comput
【在 g*********8 的大作中提到】
: could you explain your algorithm? thank you.
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