logarithm and product, which is faster?# Programming - 葵花宝典
t*d
1 楼
a = log(b*c*d*e*f)
AND
a = log(a) + log(b) + log(c) + log(f)
Which code is faster?
Thx!
AND
a = log(a) + log(b) + log(c) + log(f)
Which code is faster?
Thx!
a*a
2 楼
The former is faster, but the other is more stable from overflow.
【在 t*d 的大作中提到】
: a = log(b*c*d*e*f)
: AND
: a = log(a) + log(b) + log(c) + log(f)
: Which code is faster?
: Thx!
【在 t*d 的大作中提到】
: a = log(b*c*d*e*f)
: AND
: a = log(a) + log(b) + log(c) + log(f)
: Which code is faster?
: Thx!
a*e
3 楼
Modern compilers will consider them the same.
【在 t*d 的大作中提到】
: a = log(b*c*d*e*f)
: AND
: a = log(a) + log(b) + log(c) + log(f)
: Which code is faster?
: Thx!
【在 t*d 的大作中提到】
: a = log(b*c*d*e*f)
: AND
: a = log(a) + log(b) + log(c) + log(f)
: Which code is faster?
: Thx!
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