s*e
2 楼
【 以下文字转载自 Beijing 讨论区 】
发信人: amicus (青岚), 信区: Beijing
标 题: Re: Three People Killed, Three More Wounded In Shooting At
发信站: BBS 未名空间站 (Fri Feb 12 19:55:48 2010, 美东)
http://www.msnbc.msn.com/id/35372168/ns/us_news-crime_and_courts/?GT1=43001
Three faculty members were killed and at least three other people were
injured. Two men were in critical condition at a Huntsville hospital and a
woman was in stable condition, WHNT-TV reported.
According to media reports, Bishop had been denied tenure Friday
发信人: amicus (青岚), 信区: Beijing
标 题: Re: Three People Killed, Three More Wounded In Shooting At
发信站: BBS 未名空间站 (Fri Feb 12 19:55:48 2010, 美东)
http://www.msnbc.msn.com/id/35372168/ns/us_news-crime_and_courts/?GT1=43001
Three faculty members were killed and at least three other people were
injured. Two men were in critical condition at a Huntsville hospital and a
woman was in stable condition, WHNT-TV reported.
According to media reports, Bishop had been denied tenure Friday
x*n
3 楼
请问美联航从北京飞到旧金山后,如果是要在terminal 3再转美国国内航班,同是美联
航的班机,是从国际到达的地方出来做机场巴士,还是在里面可以走到terminal 3?转
机时间二小时。
行李通过入关检查后,可以直接在取行李的地方再次托运么?还是要拿到terminal 3去
托运?都是美联航的班机。
我没在旧金山转机过,不知道情况。父母马上要从那里入关再转机,所以想问一下情况
。
航的班机,是从国际到达的地方出来做机场巴士,还是在里面可以走到terminal 3?转
机时间二小时。
行李通过入关检查后,可以直接在取行李的地方再次托运么?还是要拿到terminal 3去
托运?都是美联航的班机。
我没在旧金山转机过,不知道情况。父母马上要从那里入关再转机,所以想问一下情况
。
W*t
4 楼
如果我作为co-founder的身份开设一个公司,我的F1身份会自动作废吗?
s*d
5 楼
想买个机箱。。。 电源已经有了。。。
k*u
6 楼
笔记本电脑win 7上虚拟机装ubuntu,有线网卡可以上网,用的bridged,各种都正常;
但是如果不用有线,用电脑自带的无线网卡,就没有办法上网。bridge,nat我都试过
,都不行;
好像就找不到网卡,为什么?
我另外插一个usb的无线网卡,也是不行。我点了右下角的符号,把usb 无线从win 7
上落到ubuntu,能看见网卡,但是不能上网
麻烦大虾们给点帮助,谢谢!!
但是如果不用有线,用电脑自带的无线网卡,就没有办法上网。bridge,nat我都试过
,都不行;
好像就找不到网卡,为什么?
我另外插一个usb的无线网卡,也是不行。我点了右下角的符号,把usb 无线从win 7
上落到ubuntu,能看见网卡,但是不能上网
麻烦大虾们给点帮助,谢谢!!
y*e
7 楼
Which of the following statements describe the results of executing the
code snippet below in C++?
int var = 1;
void main() {
int i = i;
}
A. The i within main will have an undefined value.
B. The compiler will allow this statement, but the linker will not be able
to resolve the declaration of i.
C. The i within main will have a value of 1.
D. The compiler will not allow this statement.
E. The result is compiler-dependent.
正确答案应该是什么?为什么?
觉得A和E都对。
code snippet below in C++?
int var = 1;
void main() {
int i = i;
}
A. The i within main will have an undefined value.
B. The compiler will allow this statement, but the linker will not be able
to resolve the declaration of i.
C. The i within main will have a value of 1.
D. The compiler will not allow this statement.
E. The result is compiler-dependent.
正确答案应该是什么?为什么?
觉得A和E都对。
s*6
8 楼
They look at your status, not your visa. Your visa will only be valid for 1
year, but your status is valid till the expiration of your I-20. Your
status needs to be valid in order to apply for Canadian visa.
szu2006
year, but your status is valid till the expiration of your I-20. Your
status needs to be valid in order to apply for Canadian visa.
szu2006
y*l
9 楼
是从国际到达的地方出来做机场巴士,还是在里面可以走到terminal 3?------直接在
里面走,不用做巴士。
行李通过入关检查后,可以直接在取行李的地方再次托运么?还是要拿到terminal 3去
托运?都是美联航的班机。-----我记的好象是去terminal托运,最好再问问。。。
里面走,不用做巴士。
行李通过入关检查后,可以直接在取行李的地方再次托运么?还是要拿到terminal 3去
托运?都是美联航的班机。-----我记的好象是去terminal托运,最好再问问。。。
v*e
11 楼
当然PC7B
s*n
12 楼
vm设置换成nat
guest里面用命令行:
sudo dhclient -r
sudo dhclient
guest里面用命令行:
sudo dhclient -r
sudo dhclient
l*s
13 楼
D
x*n
15 楼
谢谢,里面走就方便了。
托运的情况,我写了两种可能的情况。一是入关检查后就能找到机场托运行李的地方,
二是到了terminal再托运。
写了指南给父母用。没找到同行的,怕同机的人没有一起去转机的。以防万一。
托运的情况,我写了两种可能的情况。一是入关检查后就能找到机场托运行李的地方,
二是到了terminal再托运。
写了指南给父母用。没找到同行的,怕同机的人没有一起去转机的。以防万一。
k*u
17 楼
谢谢
回家试试看
回家试试看
f*c
18 楼
学习中,坐等高手来讲课。
我在linux上试了,编译通过,加上cout<哪个对呢?
我在linux上试了,编译通过,加上cout<哪个对呢?
k*u
21 楼
试了这两个命令
还是不能上网啊
求救!!!
谢谢
还是不能上网啊
求救!!!
谢谢
S*I
22 楼
A is correct for sure; E is somewhat correct (strictly speaking, compiler
doesn't need to handle this at all, so it is not correct to say "compiler-
dependent").
able
【在 y****e 的大作中提到】
: Which of the following statements describe the results of executing the
: code snippet below in C++?
: int var = 1;
: void main() {
: int i = i;
: }
: A. The i within main will have an undefined value.
: B. The compiler will allow this statement, but the linker will not be able
: to resolve the declaration of i.
: C. The i within main will have a value of 1.
doesn't need to handle this at all, so it is not correct to say "compiler-
dependent").
able
【在 y****e 的大作中提到】
: Which of the following statements describe the results of executing the
: code snippet below in C++?
: int var = 1;
: void main() {
: int i = i;
: }
: A. The i within main will have an undefined value.
: B. The compiler will allow this statement, but the linker will not be able
: to resolve the declaration of i.
: C. The i within main will have a value of 1.
k*u
25 楼
笔记本电脑自己的无线网卡
ubuntu下面要安装驱动么?
为什么有线网卡就能自动找到?
ubuntu下面要安装驱动么?
为什么有线网卡就能自动找到?
b*s
26 楼
一个小疑问,main()在c/c++里面,一般要返回一个int的吧
able
【在 y****e 的大作中提到】
: Which of the following statements describe the results of executing the
: code snippet below in C++?
: int var = 1;
: void main() {
: int i = i;
: }
: A. The i within main will have an undefined value.
: B. The compiler will allow this statement, but the linker will not be able
: to resolve the declaration of i.
: C. The i within main will have a value of 1.
able
【在 y****e 的大作中提到】
: Which of the following statements describe the results of executing the
: code snippet below in C++?
: int var = 1;
: void main() {
: int i = i;
: }
: A. The i within main will have an undefined value.
: B. The compiler will allow this statement, but the linker will not be able
: to resolve the declaration of i.
: C. The i within main will have a value of 1.
t*a
27 楼
钱多想耍酷就买lian-li, 用的是铝, 不隔音但很好看.
想安静就买antec, 用料朴实(钢板)但份量沉
想安静就买antec, 用料朴实(钢板)但份量沉
k*d
32 楼
我也遇到类似的问题。我在window7里disable有线网卡,然后就用nat就行了。
如果要两个网卡都能用,好像要改vmplayer的配置文件,让vmplayer知道有多个网卡。
谁要是搞清楚了,麻烦告诉一下。
【在 k*****u 的大作中提到】
: 笔记本电脑win 7上虚拟机装ubuntu,有线网卡可以上网,用的bridged,各种都正常;
: 但是如果不用有线,用电脑自带的无线网卡,就没有办法上网。bridge,nat我都试过
: ,都不行;
: 好像就找不到网卡,为什么?
: 我另外插一个usb的无线网卡,也是不行。我点了右下角的符号,把usb 无线从win 7
: 上落到ubuntu,能看见网卡,但是不能上网
: 麻烦大虾们给点帮助,谢谢!!
如果要两个网卡都能用,好像要改vmplayer的配置文件,让vmplayer知道有多个网卡。
谁要是搞清楚了,麻烦告诉一下。
【在 k*****u 的大作中提到】
: 笔记本电脑win 7上虚拟机装ubuntu,有线网卡可以上网,用的bridged,各种都正常;
: 但是如果不用有线,用电脑自带的无线网卡,就没有办法上网。bridge,nat我都试过
: ,都不行;
: 好像就找不到网卡,为什么?
: 我另外插一个usb的无线网卡,也是不行。我点了右下角的符号,把usb 无线从win 7
: 上落到ubuntu,能看见网卡,但是不能上网
: 麻烦大虾们给点帮助,谢谢!!
b*s
33 楼
觉得是d
void main()应该不能通过编译
able
【在 y****e 的大作中提到】
: Which of the following statements describe the results of executing the
: code snippet below in C++?
: int var = 1;
: void main() {
: int i = i;
: }
: A. The i within main will have an undefined value.
: B. The compiler will allow this statement, but the linker will not be able
: to resolve the declaration of i.
: C. The i within main will have a value of 1.
void main()应该不能通过编译
able
【在 y****e 的大作中提到】
: Which of the following statements describe the results of executing the
: code snippet below in C++?
: int var = 1;
: void main() {
: int i = i;
: }
: A. The i within main will have an undefined value.
: B. The compiler will allow this statement, but the linker will not be able
: to resolve the declaration of i.
: C. The i within main will have a value of 1.
k*u
36 楼
用有线网卡的ifconfig的结果
eth0 Link encap:Ethernet HWaddr 00:0c:29:a0:34:e4
inet addr:138.23.191.192 Bcast:138.23.191.255 Mask:255.255.254.0
inet6 addr: fe80::20c:29ff:fea0:34e4/64 Scope:Link
UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1
RX packets:4571 errors:0 dropped:0 overruns:0 frame:0
TX packets:1446 errors:0 dropped:0 overruns:0 carrier:0
collisions:0 txqueuelen:1000
RX bytes:2107491 (2.1 MB) TX bytes:246723 (246.7 KB)
Interrupt:19 Base address:0x2000
lo Link encap:Local Loopback
inet addr:127.0.0.1 Mask:255.0.0.0
inet6 addr: ::1/128 Scope:Host
UP LOOPBACK RUNNING MTU:16436 Metric:1
RX packets:44 errors:0 dropped:0 overruns:0 frame:0
TX packets:44 errors:0 dropped:0 overruns:0 carrier:0
collisions:0 txqueuelen:0
RX bytes:3312 (3.3 KB) TX bytes:3312 (3.3 KB)
用无限网卡的结果
eth0 Link encap:Ethernet HWaddr 00:0c:29:a0:34:e4
inet6 addr: fe80::20c:29ff:fea0:34e4/64 Scope:Link
UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1
RX packets:7137 errors:0 dropped:0 overruns:0 frame:0
TX packets:1535 errors:0 dropped:0 overruns:0 carrier:0
collisions:0 txqueuelen:1000
RX bytes:2524784 (2.5 MB) TX bytes:263387 (263.3 KB)
Interrupt:19 Base address:0x2000
lo Link encap:Local Loopback
inet addr:127.0.0.1 Mask:255.0.0.0
inet6 addr: ::1/128 Scope:Host
UP LOOPBACK RUNNING MTU:16436 Metric:1
RX packets:45 errors:0 dropped:0 overruns:0 frame:0
TX packets:45 errors:0 dropped:0 overruns:0 carrier:0
collisions:0 txqueuelen:0
RX bytes:3888 (3.8 KB) TX bytes:3888 (3.8 KB)
eth0 Link encap:Ethernet HWaddr 00:0c:29:a0:34:e4
inet addr:138.23.191.192 Bcast:138.23.191.255 Mask:255.255.254.0
inet6 addr: fe80::20c:29ff:fea0:34e4/64 Scope:Link
UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1
RX packets:4571 errors:0 dropped:0 overruns:0 frame:0
TX packets:1446 errors:0 dropped:0 overruns:0 carrier:0
collisions:0 txqueuelen:1000
RX bytes:2107491 (2.1 MB) TX bytes:246723 (246.7 KB)
Interrupt:19 Base address:0x2000
lo Link encap:Local Loopback
inet addr:127.0.0.1 Mask:255.0.0.0
inet6 addr: ::1/128 Scope:Host
UP LOOPBACK RUNNING MTU:16436 Metric:1
RX packets:44 errors:0 dropped:0 overruns:0 frame:0
TX packets:44 errors:0 dropped:0 overruns:0 carrier:0
collisions:0 txqueuelen:0
RX bytes:3312 (3.3 KB) TX bytes:3312 (3.3 KB)
用无限网卡的结果
eth0 Link encap:Ethernet HWaddr 00:0c:29:a0:34:e4
inet6 addr: fe80::20c:29ff:fea0:34e4/64 Scope:Link
UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1
RX packets:7137 errors:0 dropped:0 overruns:0 frame:0
TX packets:1535 errors:0 dropped:0 overruns:0 carrier:0
collisions:0 txqueuelen:1000
RX bytes:2524784 (2.5 MB) TX bytes:263387 (263.3 KB)
Interrupt:19 Base address:0x2000
lo Link encap:Local Loopback
inet addr:127.0.0.1 Mask:255.0.0.0
inet6 addr: ::1/128 Scope:Host
UP LOOPBACK RUNNING MTU:16436 Metric:1
RX packets:45 errors:0 dropped:0 overruns:0 frame:0
TX packets:45 errors:0 dropped:0 overruns:0 carrier:0
collisions:0 txqueuelen:0
RX bytes:3888 (3.8 KB) TX bytes:3888 (3.8 KB)
f*c
37 楼
update, 昨天code测试直接用了int main()。
用gcc version 4.4.5 (Debian 4.4.5-8)编译不通过,“test.cpp:7: error: ‘::
main’ must return ‘int’”
所以答案是D。
用gcc version 4.4.5 (Debian 4.4.5-8)编译不通过,“test.cpp:7: error: ‘::
main’ must return ‘int’”
所以答案是D。
k*u
38 楼
我是用的vmware 这个没问题
刚才虚拟机上的xp实验了一下
主机有线,如果bridge,xp可以上网。如果nat,xp也不能上
如果主机无限,只有主机能上,虚拟机怎么都不能上
刚才虚拟机上的xp实验了一下
主机有线,如果bridge,xp可以上网。如果nat,xp也不能上
如果主机无限,只有主机能上,虚拟机怎么都不能上
n*e
43 楼
=== 错误应该是在这里!i没定义就用了,所以编译通不过。
able
【在 y****e 的大作中提到】
: Which of the following statements describe the results of executing the
: code snippet below in C++?
: int var = 1;
: void main() {
: int i = i;
: }
: A. The i within main will have an undefined value.
: B. The compiler will allow this statement, but the linker will not be able
: to resolve the declaration of i.
: C. The i within main will have a value of 1.
L*1
46 楼
这是真正CS应该知道的。吗工不管有没有CS学位,都不该关心这类事情,因为有的常识
的吗工都不会写这样的code。
的吗工都不会写这样的code。
m*7
48 楼
result就是写这个代码的码农如果是有意的应该被开除了去
c*n
52 楼
这个问题的确考了一些平时自己想当然而没有深究的东西。
1) int i = i;
这个相当于
int i; //define and allocate storage on stack.
i = i; // assignment operator.
所以 i 是 uninitialized. 选 A)
2) void main()
研究了一下。 对main()的prototype, C/C++ 不同的年代的标准有不同的要求
C-90: 应该return int, 但允许compiler自由加入对其他return type的support.
也就是说, void main(), float main()都可能被你的compiler 支持。
C-99: 同 C-90
C++: 只允许 int main();
gcc 选择了支持 void main().
g++ 没得选, 不能支持 void main().
由以下结果也可看出结论:
gcc -std=c99 // ok;
gcc -pedantic -std=c99 // warning: return type of ‘main’ is not ‘int’ [-
Wmain]
g++ // error: ‘::main’ must return ‘int’
所以D 应为:The compiler **may or may not** allow this statement
E: 不知道这里的 result 指的是什么
=================================================================
int var = 1;
void main() {
int i = i;
}
A. The i within main will have an undefined value.
B. The compiler will allow this statement, but the linker will not be able
to resolve the declaration of i.
C. The i within main will have a value of 1.
D. The compiler will not allow this statement.
E. The result is compiler-dependent.
1) int i = i;
这个相当于
int i; //define and allocate storage on stack.
i = i; // assignment operator.
所以 i 是 uninitialized. 选 A)
2) void main()
研究了一下。 对main()的prototype, C/C++ 不同的年代的标准有不同的要求
C-90: 应该return int, 但允许compiler自由加入对其他return type的support.
也就是说, void main(), float main()都可能被你的compiler 支持。
C-99: 同 C-90
C++: 只允许 int main();
gcc 选择了支持 void main().
g++ 没得选, 不能支持 void main().
由以下结果也可看出结论:
gcc -std=c99 // ok;
gcc -pedantic -std=c99 // warning: return type of ‘main’ is not ‘int’ [-
Wmain]
g++ // error: ‘::main’ must return ‘int’
所以D 应为:The compiler **may or may not** allow this statement
E: 不知道这里的 result 指的是什么
=================================================================
int var = 1;
void main() {
int i = i;
}
A. The i within main will have an undefined value.
B. The compiler will allow this statement, but the linker will not be able
to resolve the declaration of i.
C. The i within main will have a value of 1.
D. The compiler will not allow this statement.
E. The result is compiler-dependent.
t*t
53 楼
第一个就错了, "int i=i;" 和"int i; i=i;"在C++里是两个不同的东西. 第一个形式
是undefined (unless another "i" can be found in other scope), 因为
"... an initializer in the definition of a variable can consist of arbitrary
expressions involving literals and previously declared variables and
functions, regardless of the variable's storage duration." [8.5, clause 2]
注意, initializer expression must only involve "*previously* declared"
variables and functions...
当然, 我支持不应该考这些, 但是如果你要研究的话, 没有理由得到一个错误的结论.
【在 c*****n 的大作中提到】
: 这个问题的确考了一些平时自己想当然而没有深究的东西。
: 1) int i = i;
: 这个相当于
: int i; //define and allocate storage on stack.
: i = i; // assignment operator.
: 所以 i 是 uninitialized. 选 A)
: 2) void main()
: 研究了一下。 对main()的prototype, C/C++ 不同的年代的标准有不同的要求
: C-90: 应该return int, 但允许compiler自由加入对其他return type的support.
: 也就是说, void main(), float main()都可能被你的compiler 支持。
是undefined (unless another "i" can be found in other scope), 因为
"... an initializer in the definition of a variable can consist of arbitrary
expressions involving literals and previously declared variables and
functions, regardless of the variable's storage duration." [8.5, clause 2]
注意, initializer expression must only involve "*previously* declared"
variables and functions...
当然, 我支持不应该考这些, 但是如果你要研究的话, 没有理由得到一个错误的结论.
【在 c*****n 的大作中提到】
: 这个问题的确考了一些平时自己想当然而没有深究的东西。
: 1) int i = i;
: 这个相当于
: int i; //define and allocate storage on stack.
: i = i; // assignment operator.
: 所以 i 是 uninitialized. 选 A)
: 2) void main()
: 研究了一下。 对main()的prototype, C/C++ 不同的年代的标准有不同的要求
: C-90: 应该return int, 但允许compiler自由加入对其他return type的support.
: 也就是说, void main(), float main()都可能被你的compiler 支持。
t*t
54 楼
对于main()的定义, C 和C++实际上是没差别的. C++和C一样允许freestanding
environment, 这时你也可以不定义main(). 但是在hosted environment, C和C++都要
求main()必须返回int.
【在 c*****n 的大作中提到】
: 这个问题的确考了一些平时自己想当然而没有深究的东西。
: 1) int i = i;
: 这个相当于
: int i; //define and allocate storage on stack.
: i = i; // assignment operator.
: 所以 i 是 uninitialized. 选 A)
: 2) void main()
: 研究了一下。 对main()的prototype, C/C++ 不同的年代的标准有不同的要求
: C-90: 应该return int, 但允许compiler自由加入对其他return type的support.
: 也就是说, void main(), float main()都可能被你的compiler 支持。
environment, 这时你也可以不定义main(). 但是在hosted environment, C和C++都要
求main()必须返回int.
【在 c*****n 的大作中提到】
: 这个问题的确考了一些平时自己想当然而没有深究的东西。
: 1) int i = i;
: 这个相当于
: int i; //define and allocate storage on stack.
: i = i; // assignment operator.
: 所以 i 是 uninitialized. 选 A)
: 2) void main()
: 研究了一下。 对main()的prototype, C/C++ 不同的年代的标准有不同的要求
: C-90: 应该return int, 但允许compiler自由加入对其他return type的support.
: 也就是说, void main(), float main()都可能被你的compiler 支持。
S*I
56 楼
"A hosted environment is one that provides the standard libraries. The
standard permits both hosted and freestanding environments. and goes to some
length to differentiate between them. Who would want to go without
libraries? Well, anybody writing 'stand alone' programs. Operating systems,
embedded systems like machine controllers and firmware for instrumentation
are all examples of the case where a hosted environment might be
inappropriate. Programs written for a hosted environment have to be aware of
the fact that the names of all the library functions are reserved for use
by the implementation. There is no such restriction on the programmer
working in a freestanding environment, although it isn't a good idea to go
using names that are used in the standard library, simply because it will
mislead readers of the program."
【在 k****5 的大作中提到】
: 大牛指点一下,啥是freestanding environment? hosted environment?
standard permits both hosted and freestanding environments. and goes to some
length to differentiate between them. Who would want to go without
libraries? Well, anybody writing 'stand alone' programs. Operating systems,
embedded systems like machine controllers and firmware for instrumentation
are all examples of the case where a hosted environment might be
inappropriate. Programs written for a hosted environment have to be aware of
the fact that the names of all the library functions are reserved for use
by the implementation. There is no such restriction on the programmer
working in a freestanding environment, although it isn't a good idea to go
using names that are used in the standard library, simply because it will
mislead readers of the program."
【在 k****5 的大作中提到】
: 大牛指点一下,啥是freestanding environment? hosted environment?
m*l
63 楼
刚才午睡前翻书看到BS说这个问题,你说错了
arbitrary
【在 t****t 的大作中提到】
: 第一个就错了, "int i=i;" 和"int i; i=i;"在C++里是两个不同的东西. 第一个形式
: 是undefined (unless another "i" can be found in other scope), 因为
: "... an initializer in the definition of a variable can consist of arbitrary
: expressions involving literals and previously declared variables and
: functions, regardless of the variable's storage duration." [8.5, clause 2]
: 注意, initializer expression must only involve "*previously* declared"
: variables and functions...
: 当然, 我支持不应该考这些, 但是如果你要研究的话, 没有理由得到一个错误的结论.
arbitrary
【在 t****t 的大作中提到】
: 第一个就错了, "int i=i;" 和"int i; i=i;"在C++里是两个不同的东西. 第一个形式
: 是undefined (unless another "i" can be found in other scope), 因为
: "... an initializer in the definition of a variable can consist of arbitrary
: expressions involving literals and previously declared variables and
: functions, regardless of the variable's storage duration." [8.5, clause 2]
: 注意, initializer expression must only involve "*previously* declared"
: variables and functions...
: 当然, 我支持不应该考这些, 但是如果你要研究的话, 没有理由得到一个错误的结论.
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