FF的泰普# bagua - 娱乐八卦
a*l
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There is an array A[N] of N numbers. You have to compose an array Output[N]
such that Output[i] will be equal to multiplication of all the elements of A
[N] except A[i]. For example Output[0] will be multiplication of A[1] to A[N
-1] and Output[1] will be multiplication of A[0] and from A[2] to A[N-1].
Solve it without division operator and in O(n).
那位达人给说一个solution?
such that Output[i] will be equal to multiplication of all the elements of A
[N] except A[i]. For example Output[0] will be multiplication of A[1] to A[N
-1] and Output[1] will be multiplication of A[0] and from A[2] to A[N-1].
Solve it without division operator and in O(n).
那位达人给说一个solution?