swap a and b using XOR (no the third variable). The following function is correct? Explain swap(int *a, int *b) { *a ^= *b ^= *a ^= *b; } I found that if I write it as follows, it's correct *a ^= *b; *b ^= *a; *a ^= *b; but *a ^= *b ^= *a ^= *b is wrong but why? explain in detail
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【在 d*******n 的大作中提到】 : swap a and b using XOR (no the third variable). The following function is : correct? Explain : swap(int *a, int *b) : { : *a ^= *b ^= *a ^= *b; : } : I found that if I write it as follows, it's correct : *a ^= *b; : *b ^= *a; : *a ^= *b;
【在 d*******n 的大作中提到】 : swap a and b using XOR (no the third variable). The following function is : correct? Explain : swap(int *a, int *b) : { : *a ^= *b ^= *a ^= *b; : } : I found that if I write it as follows, it's correct : *a ^= *b; : *b ^= *a; : *a ^= *b;
U*A
11 楼
重新考GMAT吧,申请到top 5的几率会大很多。当然,我也不同意非top 5就不能读。
x*g
12 楼
I think you can overwrite the form. At least a few years back it was allowed.