m*02012-10-30 07:105 楼= e-1since, Exp[x]=1 + x + x^2/2 + x^3/(2*3) + ....x=1,e = 1 +1+1/2+1/(2*3)+1/(2*3*4)+1/(2*3*4*5)+....【在 i***5 的大作中提到】: 直到无穷,这个数列的极限值是多少?
i*52012-10-30 07:106 楼这是e的定义?谢谢【在 m****0 的大作中提到】: = e-1: since, Exp[x]=1 + x + x^2/2 + x^3/(2*3) + ....: x=1,: e = 1 +1+1/2+1/(2*3)+1/(2*3*4)+1/(2*3*4*5)+....
d*f2012-10-30 07:107 楼u r right【在 m****0 的大作中提到】: = e-1: since, Exp[x]=1 + x + x^2/2 + x^3/(2*3) + ....: x=1,: e = 1 +1+1/2+1/(2*3)+1/(2*3*4)+1/(2*3*4*5)+....