a question about regular expression# Unix - 噫吁兮，危乎高哉
w*c
1 楼
one question about regular expression:
assuming we have statement as following:
%var1%/dir:%var2%/dir:%var3%/dir
in vi, it is expected that using s/%\(.*\)%/$\1/g the above
could be converted to "$var1/dir:$var2/dir:$var3/dir".but
I found that it wound up with "$var1%/dir:%var2%/dir:%var3/dir",
that is, vi searchs for largest matchup. How could I get the
fewest match up?
it is very interesting question. hope unix guru could help me.
Acton
assuming we have statement as following:
%var1%/dir:%var2%/dir:%var3%/dir
in vi, it is expected that using s/%\(.*\)%/$\1/g the above
could be converted to "$var1/dir:$var2/dir:$var3/dir".but
I found that it wound up with "$var1%/dir:%var2%/dir:%var3/dir",
that is, vi searchs for largest matchup. How could I get the
fewest match up?
it is very interesting question. hope unix guru could help me.
Acton
