怎样打印出grep后的部分内容?# Unix - 噫吁兮,危乎高哉
t*l
1 楼
for example,
1.grep "User Name:" user.txt
User Name: John
User Name: Mary
User Name: Michael
现在我想只打印出冒号后面的名字,并使之间隔显示在同一行里.怎么实现?
thanks.
1.grep "User Name:" user.txt
User Name: John
User Name: Mary
User Name: Michael
现在我想只打印出冒号后面的名字,并使之间隔显示在同一行里.怎么实现?
thanks.