请教：函数后面的 throw() 有意义么？# Programming - 葵花宝典
t*2
1 楼
新手请教：C++有一种功能，在函数后面写throw()表示这个函数不会throw任何异常。
请问各位高手你们觉得这种功能什么意义么？如果函数想throw异常又定义了throw()是
不是会compiler-time error？
请问各位高手你们觉得这种功能什么意义么？如果函数想throw异常又定义了throw()是
不是会compiler-time error？
P*e
2 楼
ft
no error
in try block, who ever first, who throw first and then just to catch block
【在 t*********2 的大作中提到】
: 新手请教：C++有一种功能，在函数后面写throw()表示这个函数不会throw任何异常。
: 请问各位高手你们觉得这种功能什么意义么？如果函数想throw异常又定义了throw()是
: 不是会compiler-time error？
no error
in try block, who ever first, who throw first and then just to catch block
【在 t*********2 的大作中提到】
: 新手请教：C++有一种功能，在函数后面写throw()表示这个函数不会throw任何异常。
: 请问各位高手你们觉得这种功能什么意义么？如果函数想throw异常又定义了throw()是
: 不是会compiler-time error？
t*2
3 楼
no, my case is:
An exception specification with an empty throw, as in
void MyFunction(int i) throw(){
}
tells the compiler that the function does not throw any exceptions.
【在 P********e 的大作中提到】
: ft
: no error
: in try block, who ever first, who throw first and then just to catch block
An exception specification with an empty throw, as in
void MyFunction(int i) throw(){
}
tells the compiler that the function does not throw any exceptions.
【在 P********e 的大作中提到】
: ft
: no error
: in try block, who ever first, who throw first and then just to catch block
P*e
4 楼
大牛都去吃饭了
Here it is:
void translate() throw(unknown_word,bad_grammar) { /* ... */ }
explicitly states that it will only throw exception objects whose types are
unknown_word or bad_grammar, or any type derived from unknown_word or bad_
grammar
void foo() throw(){}
which means foo() cannot throw any exception
【在 t*********2 的大作中提到】
: no, my case is:
: An exception specification with an empty throw, as in
: void MyFunction(int i) throw(){
: }
: tells the compiler that the function does not throw any exceptions.
Here it is:
void translate() throw(unknown_word,bad_grammar) { /* ... */ }
explicitly states that it will only throw exception objects whose types are
unknown_word or bad_grammar, or any type derived from unknown_word or bad_
grammar
void foo() throw(){}
which means foo() cannot throw any exception
【在 t*********2 的大作中提到】
: no, my case is:
: An exception specification with an empty throw, as in
: void MyFunction(int i) throw(){
: }
: tells the compiler that the function does not throw any exceptions.
t*t
5 楼
你把最重要的一点漏掉了:
如果出现了意料之外的exception类型,则调用unexpected().
are
【在 P********e 的大作中提到】
: 大牛都去吃饭了
: Here it is:
: void translate() throw(unknown_word,bad_grammar) { /* ... */ }
: explicitly states that it will only throw exception objects whose types are
: unknown_word or bad_grammar, or any type derived from unknown_word or bad_
: grammar
: void foo() throw(){}
: which means foo() cannot throw any exception
如果出现了意料之外的exception类型,则调用unexpected().
are
【在 P********e 的大作中提到】
: 大牛都去吃饭了
: Here it is:
: void translate() throw(unknown_word,bad_grammar) { /* ... */ }
: explicitly states that it will only throw exception objects whose types are
: unknown_word or bad_grammar, or any type derived from unknown_word or bad_
: grammar
: void foo() throw(){}
: which means foo() cannot throw any exception
P*e
6 楼
he just wanna know, what does this mean
i*y
7 楼
这个问题我也疑惑了很久，下面的代码会有编译错误吗？
void ff() throw(int)
{
throw "error" ;
}
are
【在 P********e 的大作中提到】
: 大牛都去吃饭了
: Here it is:
: void translate() throw(unknown_word,bad_grammar) { /* ... */ }
: explicitly states that it will only throw exception objects whose types are
: unknown_word or bad_grammar, or any type derived from unknown_word or bad_
: grammar
: void foo() throw(){}
: which means foo() cannot throw any exception
void ff() throw(int)
{
throw "error" ;
}
are
【在 P********e 的大作中提到】
: 大牛都去吃饭了
: Here it is:
: void translate() throw(unknown_word,bad_grammar) { /* ... */ }
: explicitly states that it will only throw exception objects whose types are
: unknown_word or bad_grammar, or any type derived from unknown_word or bad_
: grammar
: void foo() throw(){}
: which means foo() cannot throw any exception
c*g
8 楼
编译没错，按标准运行的时候会有unexception
实际情况是有的compile也不会强制specification，比如MS VC
【在 i*****y 的大作中提到】
: 这个问题我也疑惑了很久，下面的代码会有编译错误吗？
: void ff() throw(int)
: {
: throw "error" ;
: }
:
: are
实际情况是有的compile也不会强制specification，比如MS VC
【在 i*****y 的大作中提到】
: 这个问题我也疑惑了很久，下面的代码会有编译错误吗？
: void ff() throw(int)
: {
: throw "error" ;
: }
:
: are
T*B
9 楼
Following declaration gives a message to the user of your class: my method
doesn't throw any exception. Don't bother to put a try/catch block around it
when you use it.
void A::foo() throw();
It's your responsibility not to throw an exception in the definition of your
method. Say
void A::foo() throw() {
throw (5); // you are doomed here.
}
The compiler won't give an error on above code. But you will get a run time
error (your program aborts) if you implemented it this way.
doesn't throw any exception. Don't bother to put a try/catch block around it
when you use it.
void A::foo() throw();
It's your responsibility not to throw an exception in the definition of your
method. Say
void A::foo() throw() {
throw (5); // you are doomed here.
}
The compiler won't give an error on above code. But you will get a run time
error (your program aborts) if you implemented it this way.
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