K*3
2 楼
公司简介：
美国金桥教育是定位于高端国际教育服务的机构，旨在推广、引进、整合美国先进
的教育资源，为来美留学的中国学生提供高端教育咨询服务，帮助学生找到合适自己发
展的学校和教育模式。公司拥有专业资深留学顾问，课业辅导顾问，就业辅导咨询师及
法律顾问，为来美的中国留学生的学习、生活、就业、移民，进行全程全方位的保驾护
航。
随着公司迅速地发展壮大以及开拓中国市场的需要，我们欢迎有更多富有创业激情
、踏实肯干、有独特想法和见解的优秀人才加入进来，扩充公司规模，与公司共同成长
与发展。现招聘以下的实习生（CPT & OPT），兼职，全职职位，以及公司合伙人，薪
资面谈。
美国工作的员工不受地理位置限制，同时也可以选择在中国北京、上海及成都的分
公司工作。公司可以为优秀员工办理工作身份签证，不需要解决身份者优先。欢迎没有
工作经验者加入，有相关工作经验或学生会活动经验者优先考虑。
1. 留学申请专员
职位职责：
帮助中国学生申请美国高中，大学，研究生及转学；搜集整理客户资料，制定合理
的申请时间安排计划；为客户选择申请学校，填写申请表，完成各项申请文书的准备及
修改工作，提交相关材料，完成整个申请过程。
职位要求：
拥有美国学位或本科在读第二年以上，拥有美国高中学历者优先；了解美国教育体
系，熟悉高中、大学或研究生的申请流程；有很强的英文写作能力；熟练使用MS
Office 办公软件；有留学申请经验者优先。全职两名，兼职三名。
2. 冬、夏令营活动策划执行助理
职位职责：
负责冬、夏令营的活动咨询业务；策划、书写商业活动计划方案；负责各项活动事
宜组织、安排及执行工作；负责各个活动部门、中国、美国机构的沟通协调工作；灵活
处理活动中的紧急状况。
职位要求：
拥有美国学位或本科在读第二年以上；思维活跃，勇于创新，能够承受工作压力；
吃苦耐劳，具备很强的学习能力、沟通能力和团队工作精神；积极主动，责任心强，能
够按时完成工作任务；有工作经验或学生会活动者优先。
3. 市场开发人员
职位职责：
负责冬、夏令营，留学申请，合作办学的市场开发工作，了解市场需求，开拓新市
场，积极、热情投身教育事业的市场开发，将中国的人脉资源能够转化为公司客户；研
究目前留学市场的基本情况和发展趋势。
职位要求：
具备很强的学习能力、沟通能力和团队工作精神；有良好的方案策划书写能力与口
头表达能力（中英文）；能够敏锐发现商机，了解客户心理。与国内留学客户群有联系
者优先；有意向回国开发国内市场者优先。兼职、全职均可。
4. 后续服务顾问
职位职责：
帮助高中或大学生适应美国学习生活，制定学业规划；帮助客户解决生活中的问题
，包括：接机，开办银行账户、手机卡等；提供留学美国的学业安排规划的咨询和指导
，指导学生制订学习计划；与已有客户保持联系，搜集反馈意见。
职位要求：
拥有美国学位或本科在读第二年以上；有很强的亲和力，理解力和沟通能力有很强
的语言表达能力和沟通能力；有很强的组织协调能力，细心、认真，善于合理安排行程
、计划；有很强的适应性和应变能力，能够灵活处理突发问题；有工作经验、实习经历
或学生会活动经历优先；拥有有效合法驾照。兼职，美国地理位置不限。
5. 房地产业务代表 助理
职位职责：
为公司提供接待咨询地产客户服务。介绍公司地产服务项目，了解客户需求，做市
场调研；搜寻地产资料，找到符合客户需求的地产；提供后续客户服务，跟进客户需求.
职位要求：
具有房地产相关领域必备的基础知识；具备从事房地产销售、房地产评估和房地产
策划的基本能力和基本技能；具有良好的专业素养和优秀的口头表达能力（中英文）；
拥有地产投资背景者优先。兼职两名。
6. 移民咨询顾问助理
职位职责：
帮助移民的客户整理相关申请材料。提供移民政策及相关签证、移民申请过程的咨
询服务；协助客户办理与移民相关的文件证明，协助客户解决移民过程中所遇到的问题
；协调项目方、客户及律师之间的沟通交流。
职位要求：
本科及以上学历，有法律背景；了解基本的移民政策，对海外相关政策法令最新动
向有所关注；能够协助客户准备移民所需的申请材料，办理学历、体检、经济等证明文
件和公证等；具有良好的中英文撰写能力与中英文沟通能力 。兼职两名，可培训。
7. 网站设计人员
职位职责：
完善公司的网站架构，对公司的网站进行优化设计；及时完成与公司相关的公开咨
询发布；参与公司文案宣传的设计工作。
职位要求：
拥有计算机专业背景或网站设计经验；具备优秀的网站设计能力，熟悉主流浏览器
，精通网页制作及宣传资料设计软件；能综合运用各类软件设计视觉创意网站；具有良
好的艺术触觉和美术色彩搭配功底；有网站设计经验者优先。兼职一名。
有意向者，请发英文简历及职位申请书到
Email: i**[email protected]
Tel: (732) 658-4218
Add: 1967 Lincoln Hwy, Suite 31, Edison, NJ 08817
www.goldenbridgeeducation.com
美国金桥教育是定位于高端国际教育服务的机构，旨在推广、引进、整合美国先进
的教育资源，为来美留学的中国学生提供高端教育咨询服务，帮助学生找到合适自己发
展的学校和教育模式。公司拥有专业资深留学顾问，课业辅导顾问，就业辅导咨询师及
法律顾问，为来美的中国留学生的学习、生活、就业、移民，进行全程全方位的保驾护
航。
随着公司迅速地发展壮大以及开拓中国市场的需要，我们欢迎有更多富有创业激情
、踏实肯干、有独特想法和见解的优秀人才加入进来，扩充公司规模，与公司共同成长
与发展。现招聘以下的实习生（CPT & OPT），兼职，全职职位，以及公司合伙人，薪
资面谈。
美国工作的员工不受地理位置限制，同时也可以选择在中国北京、上海及成都的分
公司工作。公司可以为优秀员工办理工作身份签证，不需要解决身份者优先。欢迎没有
工作经验者加入，有相关工作经验或学生会活动经验者优先考虑。
1. 留学申请专员
职位职责：
帮助中国学生申请美国高中，大学，研究生及转学；搜集整理客户资料，制定合理
的申请时间安排计划；为客户选择申请学校，填写申请表，完成各项申请文书的准备及
修改工作，提交相关材料，完成整个申请过程。
职位要求：
拥有美国学位或本科在读第二年以上，拥有美国高中学历者优先；了解美国教育体
系，熟悉高中、大学或研究生的申请流程；有很强的英文写作能力；熟练使用MS
Office 办公软件；有留学申请经验者优先。全职两名，兼职三名。
2. 冬、夏令营活动策划执行助理
职位职责：
负责冬、夏令营的活动咨询业务；策划、书写商业活动计划方案；负责各项活动事
宜组织、安排及执行工作；负责各个活动部门、中国、美国机构的沟通协调工作；灵活
处理活动中的紧急状况。
职位要求：
拥有美国学位或本科在读第二年以上；思维活跃，勇于创新，能够承受工作压力；
吃苦耐劳，具备很强的学习能力、沟通能力和团队工作精神；积极主动，责任心强，能
够按时完成工作任务；有工作经验或学生会活动者优先。
3. 市场开发人员
职位职责：
负责冬、夏令营，留学申请，合作办学的市场开发工作，了解市场需求，开拓新市
场，积极、热情投身教育事业的市场开发，将中国的人脉资源能够转化为公司客户；研
究目前留学市场的基本情况和发展趋势。
职位要求：
具备很强的学习能力、沟通能力和团队工作精神；有良好的方案策划书写能力与口
头表达能力（中英文）；能够敏锐发现商机，了解客户心理。与国内留学客户群有联系
者优先；有意向回国开发国内市场者优先。兼职、全职均可。
4. 后续服务顾问
职位职责：
帮助高中或大学生适应美国学习生活，制定学业规划；帮助客户解决生活中的问题
，包括：接机，开办银行账户、手机卡等；提供留学美国的学业安排规划的咨询和指导
，指导学生制订学习计划；与已有客户保持联系，搜集反馈意见。
职位要求：
拥有美国学位或本科在读第二年以上；有很强的亲和力，理解力和沟通能力有很强
的语言表达能力和沟通能力；有很强的组织协调能力，细心、认真，善于合理安排行程
、计划；有很强的适应性和应变能力，能够灵活处理突发问题；有工作经验、实习经历
或学生会活动经历优先；拥有有效合法驾照。兼职，美国地理位置不限。
5. 房地产业务代表 助理
职位职责：
为公司提供接待咨询地产客户服务。介绍公司地产服务项目，了解客户需求，做市
场调研；搜寻地产资料，找到符合客户需求的地产；提供后续客户服务，跟进客户需求.
职位要求：
具有房地产相关领域必备的基础知识；具备从事房地产销售、房地产评估和房地产
策划的基本能力和基本技能；具有良好的专业素养和优秀的口头表达能力（中英文）；
拥有地产投资背景者优先。兼职两名。
6. 移民咨询顾问助理
职位职责：
帮助移民的客户整理相关申请材料。提供移民政策及相关签证、移民申请过程的咨
询服务；协助客户办理与移民相关的文件证明，协助客户解决移民过程中所遇到的问题
；协调项目方、客户及律师之间的沟通交流。
职位要求：
本科及以上学历，有法律背景；了解基本的移民政策，对海外相关政策法令最新动
向有所关注；能够协助客户准备移民所需的申请材料，办理学历、体检、经济等证明文
件和公证等；具有良好的中英文撰写能力与中英文沟通能力 。兼职两名，可培训。
7. 网站设计人员
职位职责：
完善公司的网站架构，对公司的网站进行优化设计；及时完成与公司相关的公开咨
询发布；参与公司文案宣传的设计工作。
职位要求：
拥有计算机专业背景或网站设计经验；具备优秀的网站设计能力，熟悉主流浏览器
，精通网页制作及宣传资料设计软件；能综合运用各类软件设计视觉创意网站；具有良
好的艺术触觉和美术色彩搭配功底；有网站设计经验者优先。兼职一名。
有意向者，请发英文简历及职位申请书到
Email: i**[email protected]
Tel: (732) 658-4218
Add: 1967 Lincoln Hwy, Suite 31, Edison, NJ 08817
www.goldenbridgeeducation.com
s*y
3 楼
如题，国内的家人不知道从哪听说了这个药，想让我帮忙买一些，但我没查到相关信息
。有人知道这个药吗？如果知道请告知，先行谢过了！
药名：超级护肝王
。有人知道这个药吗？如果知道请告知，先行谢过了！
药名：超级护肝王
r*y
4 楼
string library defines these overloaded operator +
string operator+ (const string& lhs, const string& rhs);
string operator+ (const char* lhs, const string& rhs);
string operator+ (char lhs, const string& rhs);
string operator+ (const string& lhs, const char* rhs);
string operator+ (const string& lhs, char rhs);
We know
string s = "hi" + "ji";
is not OK
If compiling this using g++ , I get the error :
invalid operands of types ‘const char [3]’ and ‘const char [3]’ to
binary ‘operator+’
I am a little confused about the error message. I think it is wrong because
the
function call is ambiguious. We can convert one or both to a string type and
then call one overloaded operator +, so it is ambiguous.
Why the complier complains about invalide operands instead of ambiguous call
?
thanks.
string operator+ (const string& lhs, const string& rhs);
string operator+ (const char* lhs, const string& rhs);
string operator+ (char lhs, const string& rhs);
string operator+ (const string& lhs, const char* rhs);
string operator+ (const string& lhs, char rhs);
We know
string s = "hi" + "ji";
is not OK
If compiling this using g++ , I get the error :
invalid operands of types ‘const char [3]’ and ‘const char [3]’ to
binary ‘operator+’
I am a little confused about the error message. I think it is wrong because
the
function call is ambiguious. We can convert one or both to a string type and
then call one overloaded operator +, so it is ambiguous.
Why the complier complains about invalide operands instead of ambiguous call
?
thanks.
g*f
5 楼
http://ori.hhs.gov/content/case-summary-doreian-bryan-w
very interesting.... And he did pass the patent bar on 2012.
very interesting.... And he did pass the patent bar on 2012.
l*6
6 楼
about 2 - 3 weeks before depart
t*t
7 楼
overloaded operator must have at least one user-defined operand. you can't
overload operator for 2 built-in operands.
【在 r*******y 的大作中提到】
: string library defines these overloaded operator +
: string operator+ (const string& lhs, const string& rhs);
: string operator+ (const char* lhs, const string& rhs);
: string operator+ (char lhs, const string& rhs);
: string operator+ (const string& lhs, const char* rhs);
: string operator+ (const string& lhs, char rhs);
: We know
: string s = "hi" + "ji";
: is not OK
: If compiling this using g++ , I get the error :
overload operator for 2 built-in operands.
【在 r*******y 的大作中提到】
: string library defines these overloaded operator +
: string operator+ (const string& lhs, const string& rhs);
: string operator+ (const char* lhs, const string& rhs);
: string operator+ (char lhs, const string& rhs);
: string operator+ (const string& lhs, const char* rhs);
: string operator+ (const string& lhs, char rhs);
: We know
: string s = "hi" + "ji";
: is not OK
: If compiling this using g++ , I get the error :
j*6
8 楼
yes, he did pass the bar, but I think he's not registered as a patent agent,
because of his unethical history. This guy's career is totally ruined... I
don't know if he's making some money from Wysebridge. Honestly, I don't
think it's worth the money to buy the pro version. You can get more
information
from reading the posts from mypatentbar.com.
because of his unethical history. This guy's career is totally ruined... I
don't know if he's making some money from Wysebridge. Honestly, I don't
think it's worth the money to buy the pro version. You can get more
information
from reading the posts from mypatentbar.com.
s*g
9 楼
really? Friend told me the earlier the cheaper
【在 l*******6 的大作中提到】
: about 2 - 3 weeks before depart
【在 l*******6 的大作中提到】
: about 2 - 3 weeks before depart
r*y
10 楼
good point. thanks a lot
【在 t****t 的大作中提到】
: overloaded operator must have at least one user-defined operand. you can't
: overload operator for 2 built-in operands.
【在 t****t 的大作中提到】
: overloaded operator must have at least one user-defined operand. you can't
: overload operator for 2 built-in operands.
j*g
11 楼
既不是越早越好，也不是越晚越好。机票价格随售出情况一直在变化。你永远不知道何
时最便宜。
出发前两个月-一个月算是比较合适的时间
时最便宜。
出发前两个月-一个月算是比较合适的时间
a*y
12 楼
string s = "hi" + "ji";
是不是left operand,right operand都是const char*,在5个函数里都没有这个
signature?
"At least one of the arguments used has to be a string object."
参考:
http://www.cplusplus.com/reference/string/operator+/
Parameters
lhs
A string object, a c-string or a character. Its content forms the
beginning of the returned object.
rhs
If lhs is a string object, this is another string object, a c-string or
a character.
If lhs is not a string object, this is a string object.
In either case, the content of rhs follows that of lhs in the returned
object.
Notice that at least one of the arguments used has to be a string object.
【在 r*******y 的大作中提到】
: string library defines these overloaded operator +
: string operator+ (const string& lhs, const string& rhs);
: string operator+ (const char* lhs, const string& rhs);
: string operator+ (char lhs, const string& rhs);
: string operator+ (const string& lhs, const char* rhs);
: string operator+ (const string& lhs, char rhs);
: We know
: string s = "hi" + "ji";
: is not OK
: If compiling this using g++ , I get the error :
是不是left operand,right operand都是const char*,在5个函数里都没有这个
signature?
"At least one of the arguments used has to be a string object."
参考:
http://www.cplusplus.com/reference/string/operator+/
Parameters
lhs
A string object, a c-string or a character. Its content forms the
beginning of the returned object.
rhs
If lhs is a string object, this is another string object, a c-string or
a character.
If lhs is not a string object, this is a string object.
In either case, the content of rhs follows that of lhs in the returned
object.
Notice that at least one of the arguments used has to be a string object.
【在 r*******y 的大作中提到】
: string library defines these overloaded operator +
: string operator+ (const string& lhs, const string& rhs);
: string operator+ (const char* lhs, const string& rhs);
: string operator+ (char lhs, const string& rhs);
: string operator+ (const string& lhs, const char* rhs);
: string operator+ (const string& lhs, char rhs);
: We know
: string s = "hi" + "ji";
: is not OK
: If compiling this using g++ , I get the error :
t*t
13 楼
wrong answer.
correct direction. to be precise, at least one of the operands has to be
user-defined.
【在 a***y 的大作中提到】
: string s = "hi" + "ji";
: 是不是left operand,right operand都是const char*,在5个函数里都没有这个
: signature?
: "At least one of the arguments used has to be a string object."
: 参考:
: http://www.cplusplus.com/reference/string/operator+/
: Parameters
: lhs
: A string object, a c-string or a character. Its content forms the
: beginning of the returned object.
M*t
14 楼
Since both argument expression are of const char* type
why the compiler doesn't do an automatic type conversion to convert
one of the argument to type const string&, Isn't there a
constructor in string class that enable this type conversion?
Two possible reasons
(1) Is this due to the reference symbol &, that prevents this conversion (
can't convert to a reference type?)
(2) Due to ambiguity ie. compiler doesn't know whether to convert 1st or 2nd
argument to match an overloaded operator function (both version exist).
Which one is more likely?
【在 t****t 的大作中提到】
:
: wrong answer.
: correct direction. to be precise, at least one of the operands has to be
: user-defined.
why the compiler doesn't do an automatic type conversion to convert
one of the argument to type const string&, Isn't there a
constructor in string class that enable this type conversion?
Two possible reasons
(1) Is this due to the reference symbol &, that prevents this conversion (
can't convert to a reference type?)
(2) Due to ambiguity ie. compiler doesn't know whether to convert 1st or 2nd
argument to match an overloaded operator function (both version exist).
Which one is more likely?
【在 t****t 的大作中提到】
:
: wrong answer.
: correct direction. to be precise, at least one of the operands has to be
: user-defined.
t*t
15 楼
why is it so difficult to understand? you MUST have at least one user-
defined operand, such that the compiler will start to consider using
overloaded operators.
is my english that bad?
2nd
【在 M*********t 的大作中提到】
: Since both argument expression are of const char* type
: why the compiler doesn't do an automatic type conversion to convert
: one of the argument to type const string&, Isn't there a
: constructor in string class that enable this type conversion?
: Two possible reasons
: (1) Is this due to the reference symbol &, that prevents this conversion (
: can't convert to a reference type?)
: (2) Due to ambiguity ie. compiler doesn't know whether to convert 1st or 2nd
: argument to match an overloaded operator function (both version exist).
: Which one is more likely?
defined operand, such that the compiler will start to consider using
overloaded operators.
is my english that bad?
2nd
【在 M*********t 的大作中提到】
: Since both argument expression are of const char* type
: why the compiler doesn't do an automatic type conversion to convert
: one of the argument to type const string&, Isn't there a
: constructor in string class that enable this type conversion?
: Two possible reasons
: (1) Is this due to the reference symbol &, that prevents this conversion (
: can't convert to a reference type?)
: (2) Due to ambiguity ie. compiler doesn't know whether to convert 1st or 2nd
: argument to match an overloaded operator function (both version exist).
: Which one is more likely?
M*t
16 楼
I am actually confused about what you mean by user-defined operand.
if I understand correctly you mean for a simple expression like a+b
both a and b must be of user defined type in order for a compiler
to consider using overloaded operator functions.
But for builtin type like string there are also a list of overloaded
operator functions for + (as LZ listed out)
Either your concept of operator overloading is wrong or I misunderstood what
you mean by user-defined operand.
【在 t****t 的大作中提到】
: why is it so difficult to understand? you MUST have at least one user-
: defined operand, such that the compiler will start to consider using
: overloaded operators.
: is my english that bad?
:
: 2nd
if I understand correctly you mean for a simple expression like a+b
both a and b must be of user defined type in order for a compiler
to consider using overloaded operator functions.
But for builtin type like string there are also a list of overloaded
operator functions for + (as LZ listed out)
Either your concept of operator overloading is wrong or I misunderstood what
you mean by user-defined operand.
【在 t****t 的大作中提到】
: why is it so difficult to understand? you MUST have at least one user-
: defined operand, such that the compiler will start to consider using
: overloaded operators.
: is my english that bad?
:
: 2nd
t*t
17 楼
user-defined type means class or struct, as opposed to built-in type such as
int, char, pointer.
string, is not a built-in type.
what
【在 M*********t 的大作中提到】
: I am actually confused about what you mean by user-defined operand.
: if I understand correctly you mean for a simple expression like a+b
: both a and b must be of user defined type in order for a compiler
: to consider using overloaded operator functions.
: But for builtin type like string there are also a list of overloaded
: operator functions for + (as LZ listed out)
: Either your concept of operator overloading is wrong or I misunderstood what
: you mean by user-defined operand.
int, char, pointer.
string, is not a built-in type.
what
【在 M*********t 的大作中提到】
: I am actually confused about what you mean by user-defined operand.
: if I understand correctly you mean for a simple expression like a+b
: both a and b must be of user defined type in order for a compiler
: to consider using overloaded operator functions.
: But for builtin type like string there are also a list of overloaded
: operator functions for + (as LZ listed out)
: Either your concept of operator overloading is wrong or I misunderstood what
: you mean by user-defined operand.
M*t
18 楼
Thanks, I see what you mean. string is a class type supplied by STL
so it is not a built in type,string literal like "abc" is const char*
a builtin type.
but my earlier point is rather than refuse to consider using overloaded
operator,compiler should use implicit type conversion to turn arguments into
class type and then try to match with one of the overloaded function.
This process is so called overloading resolution. Why this rule doesn't
apply here for operator function with String type, Is string special?
as
【在 t****t 的大作中提到】
: user-defined type means class or struct, as opposed to built-in type such as
: int, char, pointer.
: string, is not a built-in type.
:
: what
so it is not a built in type,string literal like "abc" is const char*
a builtin type.
but my earlier point is rather than refuse to consider using overloaded
operator,compiler should use implicit type conversion to turn arguments into
class type and then try to match with one of the overloaded function.
This process is so called overloading resolution. Why this rule doesn't
apply here for operator function with String type, Is string special?
as
【在 t****t 的大作中提到】
: user-defined type means class or struct, as opposed to built-in type such as
: int, char, pointer.
: string, is not a built-in type.
:
: what
t*t
19 楼
first of all, it is not up to you or me to say compiler "should" do what and
what. a rule is there and it applies, that's it.
second, why it is designed this way? suppose in addition to std::string, you
define another class A that can converts const char* implicitly, and also
defines operator+(A, A). now you write "abc"+"def". what does it mean? it is
not clear. it can mean string("abc")+string("def"), or means A("abc")+A("
def"), or string("abc")+A("def"), etc. basically a mess. compiler must
guarantee that, when no user-defined class is involved, everything is clear
and definite.
into
【在 M*********t 的大作中提到】
: Thanks, I see what you mean. string is a class type supplied by STL
: so it is not a built in type,string literal like "abc" is const char*
: a builtin type.
: but my earlier point is rather than refuse to consider using overloaded
: operator,compiler should use implicit type conversion to turn arguments into
: class type and then try to match with one of the overloaded function.
: This process is so called overloading resolution. Why this rule doesn't
: apply here for operator function with String type, Is string special?
:
: as
what. a rule is there and it applies, that's it.
second, why it is designed this way? suppose in addition to std::string, you
define another class A that can converts const char* implicitly, and also
defines operator+(A, A). now you write "abc"+"def". what does it mean? it is
not clear. it can mean string("abc")+string("def"), or means A("abc")+A("
def"), or string("abc")+A("def"), etc. basically a mess. compiler must
guarantee that, when no user-defined class is involved, everything is clear
and definite.
into
【在 M*********t 的大作中提到】
: Thanks, I see what you mean. string is a class type supplied by STL
: so it is not a built in type,string literal like "abc" is const char*
: a builtin type.
: but my earlier point is rather than refuse to consider using overloaded
: operator,compiler should use implicit type conversion to turn arguments into
: class type and then try to match with one of the overloaded function.
: This process is so called overloading resolution. Why this rule doesn't
: apply here for operator function with String type, Is string special?
:
: as
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