s*a
2 楼
I have a DNA molecule which is 250 kb.
The question is,
how many molecules do I have in 100 ng sample?
It bothers me for some time.
The question is,
how many molecules do I have in 100 ng sample?
It bothers me for some time.
a*x
6 楼
rough estimation would be a few billions. you calculation is definitely
wrong
wrong
f*i
7 楼
[email protected]#$
【在 c****o 的大作中提到】
: 一个90后女孩的QQ签名:“巭孬嫑莪”
: - 老夫这些字一个都读不出来,更别说写了
【在 c****o 的大作中提到】
: 一个90后女孩的QQ签名:“巭孬嫑莪”
: - 老夫这些字一个都读不出来,更别说写了
y*n
9 楼
分开念:
功夫不好不要草我。
是牛。
功夫不好不要草我。
是牛。
a*x
12 楼
The average MW is ~300, and therefore ~600 for a bp.
250kb molecular weight would be 600 x 250 x 1000 = 1.5E8;
100 ng therefore has 100E-9/1.5E8 = 6.6E-16 M
Therefore should be 6.23E23 * 6.6E-16 = 4E8 = 0.4 B
250kb molecular weight would be 600 x 250 x 1000 = 1.5E8;
100 ng therefore has 100E-9/1.5E8 = 6.6E-16 M
Therefore should be 6.23E23 * 6.6E-16 = 4E8 = 0.4 B
d*3
13 楼
功夫好不好如何衡量那,按时间算还是按流量算?
s*a
18 楼
参照 D.N.A. Box 3.3, J.M. Butler (2005) Forensic DNA Typing, 2nd Edition (
Elsevier Academic Press), p. 56
Molecular Weight of a DNA Base Pair = 618 g/mol
A = 313 g/mol;
T = 304 g/mol;
A-T base pairs = 617 g/mol
G = 329 g/mol;
C = 289 g/mol;
G-C base pairs = 618 g/mol
我用618和6.02E23的常数计算,结果是3.9E8, 最接近0.4B。
HOW:
MW of 1bp = 618 g/Mol
250 kb = 250000 bp = 250000/6.02E23 Mol= 4.15E-19 Mol
Mass of 250 kb BAC = 618*4.15E-19 g = 2.5647E-16 g = 2.5647E-7 ng
So, 100 ng of BAC contains: 100/2.5647E-7 = 3.899E8 molecules
【在 z****g 的大作中提到】
:
: ~~~~~6.02?
: My answer is 3.6E8
Elsevier Academic Press), p. 56
Molecular Weight of a DNA Base Pair = 618 g/mol
A = 313 g/mol;
T = 304 g/mol;
A-T base pairs = 617 g/mol
G = 329 g/mol;
C = 289 g/mol;
G-C base pairs = 618 g/mol
我用618和6.02E23的常数计算,结果是3.9E8, 最接近0.4B。
HOW:
MW of 1bp = 618 g/Mol
250 kb = 250000 bp = 250000/6.02E23 Mol= 4.15E-19 Mol
Mass of 250 kb BAC = 618*4.15E-19 g = 2.5647E-16 g = 2.5647E-7 ng
So, 100 ng of BAC contains: 100/2.5647E-7 = 3.899E8 molecules
【在 z****g 的大作中提到】
:
: ~~~~~6.02?
: My answer is 3.6E8
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